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Calculating days in 360-format from SYSTEMTIME

Posted on 2006-12-01
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Last Modified: 2012-06-21
Hi, I have 2 SYSTEMTIME structures and I know how to calculate the 365-day difference between them. (FILETIME int64 etc)

My problem is to calculate the total days in a 360-day format. Excel has a function Days360 which does that, but I couldn't find something in C++.

How to do it?

Regards
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Question by:WxW
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3 Comments
 
LVL 84

Expert Comment

by:ozo
ID: 18059093
#include <time.h>

int days360(time_t t1, time_t t2){
  struct tm tm1,tm2,*tm;
  tm1 = *localtime(&t1);
  tm2 = *localtime(&t2);
  if( tm1.tm_mday > 30 ){ tm1.tm_mday = 30; }
  if( tm2.tm_mday > 30 ){ tm2.tm_mday = 30; }
  return ((tm1.tm_year-tm2.tm_year)*12+tm1.tm_mon-tm2.tm_mon)*30+tm1.tm_mday-tm2.tm_mday;
}
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LVL 6

Author Comment

by:WxW
ID: 18059110
And how to convert SYSTEMTIME to a time_t ?
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LVL 84

Accepted Solution

by:
ozo earned 125 total points
ID: 18059139
int days360(SYSTEMTIME tm1, SYSTEMTIME tm2){
  if( tm1.wDay > 30 ){ tm1.wDay = 30; }
  if( tm2.WDay > 30 ){ tm2.wDay = 30; }
  return ((tm1.wYear-tm2.wYear)*12+tm1.wMonth-tm2.wMonth)*30+tm.wDay-tm2.wDay;
}
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