sqrt(double) in java.lang.Math cannot be applied to (java.lang.String)

Do a Double.parseDouble()

boefore doing a sqrt

adjustLength = (int)Math.floor(Math.sqrt(Double.parseDouble(Math.pow(adjustDisplacement.x,2.0) + Math.pow(adjustDisplacement.y,2.0))));

java.lang.Math.pow(....) returns a double; not a string.

but it takes double NOT string

i didnt notice that
but  sqrt(double) in java.lang.Math cannot be applied to (java.lang.String) means you are trying to do a sqrt on a string instead of double

   public static void main(String[] args)
    {
        int adjustLength = (int) Math.floor(Math.sqrt(Math.pow(2,2.0) + Math.pow(2,2.0)));
        System.out.println(adjustLength);
    }
works fine

dont know why you get that...

try pasting the above in your code in ur ide and see

what ide are you using

From docs; in java.lang.Math:    Neither method is overloaded.

static double       pow(double a, double b)
static double       sqrt(double a)
static double       floor(double a)


>>but  sqrt(double) in java.lang.Math cannot be applied to (java.lang.String) means you are trying to do a sqrt on a string instead of double
Indeed it does, but how did it get the String?

My best guess is that it thinks the + is the concat operator and not add



As far as I can tell, there is no String in that line of code. Hence, why I don't get it.

That works.

This also works
 public static void main(String[] args)
    {
        int adjustLength = (int) Math.floor(Math.sqrt(Math.pow(2.0,2.0) + Math.pow(2.0,2.0)));
        System.out.println(adjustLength);
    }

To be exact: I did it in the start() of an applet and not main. That shouldn't make a difference though.

Figured it out, it was an incorrect import. Two thumbs up for compiler error reporting. =)


import java.awt.geom.Point2D.Double; // This is an incorrect import of an inner class.

import java.awt.geom.Point2D; // This is correct.


Many thanks Contactkarthi.