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Is a string match comparing the values?Since it is checking if the 2 objects are the same?<br />
so,1.10 and 1.1 will be considered to be unequal?
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public class Compare<br />
{<br />
&nbsp; &nbsp; public Compare()<br />
&nbsp; &nbsp; {<br />
&nbsp; &nbsp; }<br />
<br />
&nbsp; &nbsp; public static void main(String[] args)<br />
&nbsp; &nbsp; {<br />
&nbsp; &nbsp; &nbsp; &nbsp; String s1 = &quot;40.239700&quot;;<br />
&nbsp; &nbsp; &nbsp; &nbsp; String s2 = &quot;40.2397003&quot;;<br />
<br />
&nbsp; &nbsp; &nbsp; &nbsp; System.out.println(&quot;s1.equ<wbr />als(s2)=&quot; + s1.equals(s2));<br />
&nbsp; &nbsp; &nbsp; &nbsp; System.out.println(&quot;Double<wbr />.parseDoub<wbr />le(s1)=&quot; + Double.parseDouble(s1));<br />
&nbsp; &nbsp; &nbsp; &nbsp; System.out.println(&quot;Double<wbr />.parseDoub<wbr />le(s2)=&quot; + Double.parseDouble(s2));<br />
&nbsp; &nbsp; &nbsp; &nbsp; System.out.println(&quot;Double<wbr />.parseDoub<wbr />le(s1)=Dou<wbr />ble.parseD<wbr />ouble(s2)&quot;<wbr /> + (Double.parseDouble(s1) == Double.parseDouble(s2)));<br />
&nbsp; &nbsp; &nbsp; &nbsp; System.out.println(&quot;Float.<wbr />parseFloat<wbr />(s1)=&quot; + Float.parseFloat(s1));<br />
&nbsp; &nbsp; &nbsp; &nbsp; System.out.println(&quot;Float.<wbr />parseFloat<wbr />(s2)=&quot; + Float.parseFloat(s2));<br />
<br />
&nbsp; &nbsp; &nbsp; &nbsp; System.out.println(&quot;parseF<wbr />loat.parse<wbr />Float(s1)=<wbr />parseFloat<wbr />.parseFloa<wbr />t(s2)&quot; + (Float.parseFloat(s1) == Float.parseFloat(s2)));<br />
&nbsp; &nbsp; }<br />
}<br />
<br />
Use Double.parseDouble<br />
<br />
use the above code to test
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Floating points are known to have precision errors so it is quite likely that when you used Float.parseFloat () the actual value obtained was different from what you saw in the String. Try printing it out using System.out.println () to see what it is. Using Double of course, as suggested, is the way to go.
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<a href="https://www.experts-exchange.com/questions/22404185/Is-this-purely-because-of-numerically-error-getting-un-acurate-numerical-result-on-simple-numbers.html#18582212" rel="ugc">https://www.experts-exchange.com/questions/22404185/Is-this-purely-because-of-numerically-error-getting-un-acurate-numerical-result-on-simple-numbers.html#18582212</a>
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<div class="content wysiwyg-content">
I have 2 string values s1=40.239700 and s2=40.2397003.When I compare them as strings,they are not equal ie s1.equals(s2).<br />
When I convert them to float they are found to be equal,their values when i use Float.parseFloat(s1) == Float.parseFloat(s2)<br />
are 40.2397.<br />
<br />
Also strings,-76.920200 and -76.9201965 are not equal but when I convert them to float,they become -76.9202 and are found<br />
to be equal.<br />
What is the best way to compare them
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I have 2 string values s1=40.239700 and s2=40.2397003.When I compare them as strings,they are not equal ie s1.equals(s2).
When I convert them to float they are found to be equal,their values when i use Float.parseFloat(s1) == Float.parseFloat(s2)
are 40.2397.

Also strings,-76.920200 and -76.9201965 are not equal but when I convert them to float,they become -76.9202 and are found
to be equal.
What is the best way to compare them

comparing float values vs string values

Java is a platform-independent, object-oriented programming language and run-time environment, designed to have as few implementation dependencies as possible such that developers can write one set of code across all platforms using libraries. Most devices will not run Java natively, and require a run-time component to be installed in order to execute a Java program.