hyaku
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Assigning a char to an unsign char
How do i assign a char value to an unsign char?
Assuming char val = 1;
unsigned char ch;
ch should store the value of 1 when its being assign with val.
I seems to get weird result instead..
help pls..
Assuming char val = 1;
unsigned char ch;
ch should store the value of 1 when its being assign with val.
I seems to get weird result instead..
help pls..
Last Comment
ASKER
i got other numbers instead.
if the value of val i got it from a struct, could that be the cause of it?
if the value of val i got it from a struct, could that be the cause of it?
>> i got other numbers instead.
Can you show me your exact code, and the way you "get the numbers" ?
Can you show me your exact code, and the way you "get the numbers" ?
ASKER
typedef struct{
unsigned char working[1];
} STATUS;
typedef struct{
char is_working[1];
} CHECK_STATUS;
Assuming that is_working is storing the value of 1, 1 represent working.
CHECK_STATUS cs;
STATUS s
strcpy(s.working , cs->shift_i,1);
sprintf("Working status = %1.1s", s.working);
is this correct?
unsigned char working[1];
} STATUS;
typedef struct{
char is_working[1];
} CHECK_STATUS;
Assuming that is_working is storing the value of 1, 1 represent working.
CHECK_STATUS cs;
STATUS s
strcpy(s.working , cs->shift_i,1);
sprintf("Working status = %1.1s", s.working);
is this correct?
>> is this correct?
No, there are a few problems. Try this instead :
typedef struct{
unsigned char working;
} STATUS;
typedef struct{
char is_working;
} CHECK_STATUS;
CHECK_STATUS cs;
STATUS s
s.working = cs->shift_i[0];
sprintf("Working status = %d", (int) s.working);
Howis cs->shift_i defined ?
No, there are a few problems. Try this instead :
typedef struct{
unsigned char working;
} STATUS;
typedef struct{
char is_working;
} CHECK_STATUS;
CHECK_STATUS cs;
STATUS s
s.working = cs->shift_i[0];
sprintf("Working status = %d", (int) s.working);
Howis cs->shift_i defined ?
If you're using strcpy, the size of the array has to be at least 2.
Shouldn't it be just
s.working[0] = cs.shift_i[0];
sprintf ("Working status = %d", (int) s.working[0]);
s.working gives the address of s.working. It is OK for %s as that results in the contents of what the pointer is pointing to but for %d it will just print the address.
Shouldn't it be just
s.working[0] = cs.shift_i[0];
sprintf ("Working status = %d", (int) s.working[0]);
s.working gives the address of s.working. It is OK for %s as that results in the contents of what the pointer is pointing to but for %d it will just print the address.
ASKER
sry, shift _i is actually is_working.
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ASKER
It works.
thanks for the help.
thanks for the help.
If you're using C++, just use struct instead of typedefing i.e.
struct STATUS {
unsigned char working
};
struct CHECK_STATUS {
char is_working
};
The rest of the code remains the same.
struct STATUS {
unsigned char working
};
struct CHECK_STATUS {
char is_working
};
The rest of the code remains the same.
C
C is a general-purpose, imperative computer programming language, supporting structured programming, lexical variable scope and recursion, while a static type system prevents many unintended operations. By design, C provides constructs that map efficiently to typical machine instructions, so it has found lasting use in applications that had formerly been coded in assembly language, including operating systems as well as various application software for computers ranging from supercomputers to embedded systems. It is distinct from C++ (which has its roots in C) and C#, and many later languages have borrowed directly or indirectly from C.
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unsigned char ch = val;
works perfectly. What weird result are you talking about ?