# Maxium number of values returnable by single fucntion ?

How many values can a function return ?

I have a function which accepts several pointers. It's return type is int*

If I had the following would both be returned ?

(*value01)++;
return value01;
(*value02)++;
return value02;

Or do I even need to specify a return type because the pointers would be changed whether I returned them or not ?

Thanks.
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Commented:
>> If I had the following would both be returned ?

No, you can only return one parameter. So, this code :

(*value01)++;
return value01;    //  <---- value01 will be returned
(*value02)++;       // <----- this will never be executed
return value02;    // <----- this will never be executed

There are several ways to return multiple values. Here are a few :

1) pass by pointer :

void fun(int *value01, int *value02) {
(*value01)++;
(*value02)++;
return;
}

call it like this :

int val1 = 1;
int val2 = 2;
fun(&val1, &val2);
// val1 now has value 2
// val2 now has value 3

2) pass by reference :

void fun(int &value01, int &value02) {
value01++;
value02++;
return;
}

call it like this :

int val1 = 1;
int val2 = 2;
fun(val1, val2);
// val1 now has value 2
// val2 now has value 3

3) return a struct :

struct retvals {
int val1;
int val2;
}

retvals fun(retvals vals) {
(vals.val1)++;
(vals.val2)++;
return vals;
}

call it like this :

retvals vals = { 1, 2 };
vals = fun(vals);
// vals.val1 now has value 2
// vals.val2 now has value 3
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Author Commented:

0
Commented:
As it is C++ I would suggest to create a class like
class CCounters
{
public:
CCounters(): m_Value1(0), m_Value2(0) {}
void IncValue1() {m_Value1++;}
void IncValue2() {m_Value2++};
void IncAll() {IncValue1(); IncValue2();}
private:
int  m_Value1;
int M_Value2;
}
...
CCounters Counters;
..
func(Counters);

...
void func(CCounter& rCounters)
{
....
rCounters.IncAll();
}
0
Commented:
or another function could be like;

int* returnSomething(int* p1,int* p2)
{
int* ret=new int[5];
p1++;
p2++;

for (int i=0;i<5;i++)
*(ret+i)=i;

return ret;

}

Here both p1 and p2 is modified and you also get five different value, or as much as you can

To use it;

int main()
{
x=5;y=7;
int* pf=returnSomething(&x,&y);

//now x and y are both incremented
for (int i=0;i<5;i++)
std::cout<<*(pf+i)<<std::endl;

return
}

Regards,
0
Commented:
In addition you have the memory leak.
I'm sorry, but the last suggestion I would be never recommended because it is a "dirty" solution.
I think the answer coud be:
The function can return only one value as return. This value can be a value, a pointer or a reference.

So we can return the complex object and this object can hold as many values as we need.
0
Commented:
>>In addition you have the memory leak.

int main()
{
x=5;y=7;
int* pf=returnSomething(&x,&y);

//now x and y are both incremented
for (int i=0;i<5;i++)
std::cout<<*(pf+i)<<std::endl;

delete pf; //delete the memory pointed by pf

return 0;
}

Would you still have the memory leaks?
0
Commented:
In this case not any more but in real project it is very easy to forget it.
0
Commented:
>>>  but in real project it is very easy to forget it.
Yes, normally you should delete a pointer where you created it. Only *create* functions where the only purpose is to create a new pointer are an exception from above rule. In a class you should store newly created pointers (if there is a need for pointers at all) in a data member and delete in the destructor.

Regards, Alex
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