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Evaluate Function and Chr(34) in excel vba

Posted on 2007-03-20
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Last Modified: 2012-08-13
This statement below is true, but it is not recognizing it as true. I assume it is because I need to put the Chr(34) somewhere but I do not know where I need to. Can you help me?

If Application.Evaluate(Chr(34) & InStr(r.Offset(0, VarA1).Value, VarC1) > 0 & Chr(34)) Then run code a

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Question by:tiehaze
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5 Comments
 
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byundt earned 2000 total points
ID: 18757894
Why are you using Evaluate at all? Why not:
If InStr(1, r.Offset(0, VarA1).Value, VarC1) > 0 Then 'run code a
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Author Comment

by:tiehaze
ID: 18757931
the code I am using is very complicated, I just threw in that one line

The reason I am using evaluate is because I have a variable that is equal to:
=
<> 
>
<
and the only way to use those is with evaluate.
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Author Comment

by:tiehaze
ID: 18757939
nevermind, you are correct. thanks
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LVL 81

Expert Comment

by:byundt
ID: 18757958
If you have an operator, as in your earlier question, you do not need the Chr(34) at all. This is because you are concatenating several values, and the result is a string. Putting that string inside double quotes then causes an error because the double quotes aren't required.
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LVL 85

Expert Comment

by:Rory Archibald
ID: 18757967
FYI, you only needed the CHR(34) before because you were comparing text strings ("M"="M" is true, but M=M makes Excel think M is a variable of some kind). Here you are are comparing numbers, so you wouldn't need the CHR(34).
Regards,
Rory
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