Batch file to start one program if found installed if not found start a different one

My workstations have Adobe Reader and Adobe Standard installed on them.  The executable to open pdf files is acrobat.exe in Standard version and acrord32.exe in Reader version.  Both programs are needed on workstation to work with special applications.  However, one of these Windows 3rd party application uses a .bat file to start acrord32.exe to view or print the pdf file.  However, those workstations that have the Standard version installed this batch of course if not working.  I need to modify this batch file to have it check to see if acrobat.exe is installed and if it is start the program if not found to start acrord32.  This is what the batch file currently has:

:acrobat
if (%2) == (/V) goto viewpdf
start acrord32 %2 %3
goto end

:viewpdf
start acrord32 %3
goto end

Any help would be appreciated.
clpeaseAsked:
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sirbountyCommented:
Hmm - why not let the OS choose?

:acrobat
if (%2) == (/V) goto viewpdf
start %2 %3
goto end

:viewpdf
start %3
goto end

Start should then open the PDF with the correct reader...
0
sirbountyCommented:
Otherwise, assuming the installation target is the same...

:acrobat
if (%2) == (/V) goto viewpdf
if exist "%programfiles%\Adobe Acrobat 7.0\Reader\acrord32.exe" start acrord32 %2 %3 && goto end
acrobat %2 %3
goto end

:viewpdf
start acrord32 %3
goto end
0

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clpeaseAuthor Commented:
The users I want to test this on have been out of the office.  I will have to wait until next week when they return.
0
sirbountyCommented:
Alright...keep us posted. ;^)
0
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