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Update Regx expression and Function

Posted on 2007-03-21
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Last Modified: 2010-04-23
VB.NET 2003
REGEX AND  Function need Updating:


I'am having problems with the following function below...
It is taking  normal 2 numerator and 2 denominator fractions and parsing them apart...


It should do the following:


11/2   1 1/2
11/4   1 1/4
11/8   1 1/8
21/2   2 1/2
21/4   2 1/4
21/8   2 1/8
31/2   3 1/2
31/4   3 1/4
31/8   3 1/8

or



11/16   1 1/16
21/64   2 1/64
21/32   2 1/32


it needs to leave alone double numerator and denominator
13/64
11/16
etc....


An assumption is a <space> before AND after the fraction




' regular fraction replace function
                ' dbRow.Item("fldDescription") = Regex.Replace(dbRow.Item("fldDescription"), _
                '   "(\d{2,}/\d|\d+\s+\d/\d+)", AddressOf StrFractionReplace)
                ' ===============================================
Private Function StrReplace(ByVal m As Match) As String

        Dim str As String = m.Value
        Dim strRep As String = ""

        If str.IndexOf(" "c) >= 0 Then
            Dim idx As Integer = str.IndexOf(" "c)
            strRep = str.Substring(0, idx) & "-" & str.Substring(idx + 1)
        Else
            Dim idx As Integer = str.IndexOf("/"c)
            strRep = str.Substring(0, idx - 1) & " " & str.Substring(idx - 1)
        End If

        Return strRep

    End Function


Thanks
fordraiders
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Question by:fordraiders
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3 Comments
 
LVL 63

Expert Comment

by:Fernando Soto
ID: 18764083
Hi fordraiders;

OK lets say you have the following:

31/4   3 1/4
31/8   3 1/8
11/16   1 1/16
21/64   2 1/64
21/32   2 1/32

After being processed what should they look like?

Fernando
0
 
LVL 3

Author Comment

by:fordraiders
ID: 18764199
31/4   3~1/4
31/8   3~1/8
11/16   1~1/16
21/64   2~1/64
21/32   2~1/32

Need a Tilde ~

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LVL 63

Accepted Solution

by:
Fernando Soto earned 500 total points
ID: 18764681
Hi fordraiders;

This should do what you need without the need of the StrReplace function.

        dbRow.Item("fldDescription") = Regex.Replace(dbRow.Item("fldDescription"), _
                "\s(\d)(\d/\d+)\s", "$1~$2")

The above pattern will take values like

Values to be replaced            Will be replaced with
          31/4                                         3~1/4
          31/8                                         3~1/8
          11/16                                       1~1/16
          21/64                                       2~1/64
          21/32                                       2~1/32

Fernando
0

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