Randall-B
asked on
Get Average of Numbers in a Column of HTML Table
This simple javascript calculates and displays the sum total of the 6th column in a table (which happens to have a header, then 12 rows of data, then a blank row at the bottom, where the sum of column 6 is displayed):
<script>
function calcSum(){
for (j=5;j<6;j++){
sum=0
for (i=1;i<13;i++) sum+=1*document.getElement
document.getElementById("n
}
}
</script>
Instead of showing the sum of Column 6, however, I would like to show the mean average. How would I modify the script to do that?
<script>
function calcSum(){
for (j=5;j<6;j++){
sum=0
for (i=1;i<13;i++) sum+=1*document.getElement
document.getElementById("n
}
}
</script>
Instead of showing the sum of Column 6, however, I would like to show the mean average. How would I modify the script to do that?
Shouldn't you need to divide by j*i?
document.getElementById("n
= Math.round(sum/(j*i), 2)
-r-
document.getElementById("n
= Math.round(sum/(j*i), 2)
-r-
ASKER
Tchuki,
Thanks, but dividing by j gives the wrong math average. For example, if each cell in the column has a "2" in it, the average should be 2. But this modification gave an average of 4.8 . Also, what if a cell is blank or simply has ? Then it gives an error of NaN. How can I avoid that?
Thanks, but dividing by j gives the wrong math average. For example, if each cell in the column has a "2" in it, the average should be 2. But this modification gave an average of 4.8 . Also, what if a cell is blank or simply has ? Then it gives an error of NaN. How can I avoid that?
SOLUTION
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Back to school for me ... >.<
ASKER
It seems to work if I divide by (i-1). I think that is because i is the number of data rows plus footer row. Subtracting 1 gives number of data rows only. So this seems to work:
. . . .innerHTML=sum/(i-1)
I tried to put Roonaan's rounding feature into it, also, like this:
. . . .innerHTML=Math.round(sum/
but it is rounding to 1 digit, when I actually want two decimal places. For example, it is rounding to 3 when the average is 2.77829102934 . How can I round to 2.78 , instead?
. . . .innerHTML=sum/(i-1)
I tried to put Roonaan's rounding feature into it, also, like this:
. . . .innerHTML=Math.round(sum/
but it is rounding to 1 digit, when I actually want two decimal places. For example, it is rounding to 3 when the average is 2.77829102934 . How can I round to 2.78 , instead?
ASKER
Roonan,
Your script appears to add up a sum, instead of calculating an average. But it works great for ignoring empty cells to avoid the NaN error.
How would keep that great feature of working around empty cells, but calculate the average instead of the sum? (And round to 2 decimal places)? Based on my prior post, I think it has something to do with (i-1), but that would not account for empty cells, which would make the average come out wrong. Thanks.
Your script appears to add up a sum, instead of calculating an average. But it works great for ignoring empty cells to avoid the NaN error.
How would keep that great feature of working around empty cells, but calculate the average instead of the sum? (And round to 2 decimal places)? Based on my prior post, I think it has something to do with (i-1), but that would not account for empty cells, which would make the average come out wrong. Thanks.
Yeah sorry, I was mixed up with other things. Please change:
= ints > 0 ? sum : 0;
To
= ints > 0 ? Math.round(sum/ints, 2) : 0;
= ints > 0 ? sum : 0;
To
= ints > 0 ? Math.round(sum/ints, 2) : 0;
ASKER
Roonaan,
Good, that gives the average, but it is still rounding to an single digit (integer) instead of two decimal places. For example, it rounded 2.346 to simply 3. But I would like it to round to 2.35 . How?
Good, that gives the average, but it is still rounding to an single digit (integer) instead of two decimal places. For example, it rounded 2.346 to simply 3. But I would like it to round to 2.35 . How?
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ASKER
Yes, that works. So the complete script is:
<script>
function calcSum(){
for (j=5;j<6;j++){
sum= 0;
ints =0;
for (i=1;i<13;i++) {
var value = 1*document.getElementById(
if(!isNaN(value)) { ints++; sum += value;}
}
document.getElementById("n
}
}
</script>
Thanks!
<script>
function calcSum(){
for (j=5;j<6;j++){
sum= 0;
ints =0;
for (i=1;i<13;i++) {
var value = 1*document.getElementById(
if(!isNaN(value)) { ints++; sum += value;}
}
document.getElementById("n
}
}
</script>
Thanks!
or just
(sum/ints).toFixed(2)
(sum/ints).toFixed(2)
ASKER
mplungjan: Thanks. I also appreciate how that code makes it have 2 decimal places even if it would otherwise be a single digit.
function calcSum(){
for (j=5;j<6;j++){
sum=0
for (i=1;i<13;i++) sum+=1*document.getElement
document.getElementById("n
}
}
</script>