# Query to Exclude Outliers from Selected Rows

I want to exclude outliers (the highest value and the lowest value) from a query of numerical data.  For example, if the table is like this:

ID   Student    Score
1     Doe           500
2     Doe            5
3     Doe           99
4     Doe           100
5     Doe           95
6     Doe           98
7     Doe           100
8     Smith         89
9     Smith         95
10   Smith         92
11   etc.

it is clear that Doe generally earned about 98%, but once had a strange 500% and a strange 5% (I want the query to exclude or ignore the 500 and and the 5).
1. Considering that other students besides Doe are in the table, what query could select only the rows where the student is Doe, while excluding Doe's outliers (the row with the highest value *and* the row with the lowest value)?
2.  What if I want to exclude only the row with the highest value?
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Commented:
Let's call your table "myTable". You could write the query like this:

SELECT ID, Student, Score
FROM   myTable t1
WHERE  t1.Score != (SELECT MAX(Score) FROM myTable t2 WHERE t2.ID=t1.ID)
AND      t1.Score != (SELECT MIN(Score) FROM myTable t2 WHERE t2.ID=t1.ID)
AND      t1.Student =  "Doe"
To exclude outliers for all students, simple remove the last line
To remove only the top outlier, remove the second "AND" line
Remember that you are only ever excluding the top and bottom scores. If you had a 500% and a 498% you would still see the 498%. You may choose to alter the logic to eliminate, say, anything over 100% ..

Hope this helps
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Author Commented:
hkamal,
Thanks.  My table is named "scores".  In PHP, I get the full result set when using a simple query like this:

\$sql = 'SELECT ID, Student, Score FROM scores WHERE Student = "Doe" ORDER BY Score ASC';
\$res = mysql_query(\$sql);

but I'm not getting anything (no results at all) when using the exclude-outliers query like this:

\$sql = 'SELECT ID, Student, Score FROM scores t1 WHERE  t1.Score != (SELECT MAX(Score) FROM scores t2 WHERE t2.ID=t1.ID) AND t1.Score != (SELECT MIN(Score) FROM scores t2 WHERE t2.ID=t1.ID) AND t1.Student = "Doe" ORDER BY Score ASC';
\$res = mysql_query(\$sql);

What could be wrong?
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Author Commented:
Should it be like this?

\$sql = 'SELECT ID, Student, Score FROM scores t1 WHERE t1.Student = "Doe" AND t1.Score != (SELECT MAX(Score) FROM scores t2 WHERE t2.Student="Doe") AND t1.Score != (SELECT MIN(Score) FROM scores t2 WHERE t2.Student="Doe") ORDER BY Score ASC';
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Author Commented:
Also, please see my related question at http:/Q_22463806.html , where I'm asking how to exclude the *two* highest outliers (without any arbitrary cutoffs like "100%"). Thanks.
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Author Commented:
I'm accepting your answer with the understanding that the query should be:

\$sql = 'SELECT ID, Student, Score FROM scores t1 WHERE t1.Student = "Doe" AND t1.Score != (SELECT MAX(Score) FROM scores t2 WHERE t2.Student="Doe") AND t1.Score != (SELECT MIN(Score) FROM scores t2 WHERE t2.Student="Doe") ORDER BY Score ASC';

Thanks.
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Commented:
Hi Randall-B,
I made the wrong assumption that ID was unique per Student, but I can see it is not. In which case, you can use a modified version of my query, viz:
SELECT ID, Student, Score
FROM   myTable t1
WHERE  t1.Score != (SELECT MAX(Score) FROM myTable t2 WHERE t2.Student=t1.Student)
AND      t1.Score != (SELECT MIN(Score) FROM myTable t2 WHERE t2.Student=t1.Student)
AND      t1.Student =  "Doe"
This was, all mty above statements still apply and you can still use the query for any student as long as you simply change the last line
I'll take a look at your other query
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