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Solved

Value not showing up from table in db

Posted on 2007-03-21
18
198 Views
Last Modified: 2007-03-21
I'm trying to figure out why I'm not getting the value from the database with the following code.  I know there is information for the field strProviderservice because I have already checked.  Can anyone help?

<?php
$conn = mysql_connect("127.0.0.1","root","t@rh33l");
mysql_select_db("providers",$conn);

$sql = mysql_query("SELECT strProviderservice From tblAdspace WHERE strProviderservice = '".$_POST['request']."'");

while ($row = mysql_fetch_array($sql)) {
      $strProviderservice = $row['strProviderservice'];
}
?>
<table width="275" cellpadding="5" cellspacing="0" border="0" class="cityborder" align="center">
<tr><td class="city_head" align="center" colspan="2">
Enter Your Zip Code or Town<br />
<span style="font-size: 9px; font-family: verdana; font-weight: normal">(In or near Moore County, NC)</span></td></tr>
<tr><form action="/providers.php" method="post">
<?php
if ($_REQUEST["request"] == "electrician") {
      $typeValue = "electrician";
} elseif ($_REQUEST["request"] == "painting") {
      $typeValue = "painting";
} elseif ($_REQUEST["request"] == "plumbing") {
      $typeValue = "plumbing";
}
?>
<input type="hidden" name="type" value="<?= $typeValue ?>">
<input type="hidden" name="strProviderservice" value="<?= $strProviderservice ?>">
<?= $strProviderservice?>  <----- Not getting anything ot display
0
Comment
Question by:pingeyeg
  • 8
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18 Comments
 
LVL 24

Expert Comment

by:glcummins
ID: 18766621
You should add an 'echo' in front of the variable names to get them to display:

<input type="hidden" name="type" value="<?= echo $typeValue ?>">
<input type="hidden" name="strProviderservice" value="<?= echo $strProviderservice ?>">
<?= echo $strProviderservice?>  <----- Not getting anything ot display
0
 
LVL 3

Expert Comment

by:exoska
ID: 18766649
use the
      while ($row = mysql_fetch_array($sql))
like
      while ( $row = mysql_fetch_array($sql, 'MYSQL_ASSOC' ) )
0
 
LVL 1

Author Comment

by:pingeyeg
ID: 18766651
When I place the echo command in front of the variable I get an error saying:

Parse error: parse error, expecting `','' or `';'' in /Library/WebServer/Documents/address.php on line 336

I typed <?= echo strProviderservice ?>
0
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LVL 24

Expert Comment

by:glcummins
ID: 18766670
Out of curiosity, why are you using '<?=' rather than '<?php'. I have never encountered that tag before.
0
 
LVL 1

Author Comment

by:pingeyeg
ID: 18766688
Isn't that what I am doing at the beginning exoska?

while ($row = mysql_fetch_array($sql)) {
      $strProviderservice = $row['strProviderservice'];
}
0
 
LVL 3

Expert Comment

by:exoska
ID: 18766691
if MYSQL_ASSOC does not work check if $_POST array includes the request .

try it with
   print_r($_POST);

replace all $_POST with $_REQUEST
and try that way..
0
 
LVL 24

Expert Comment

by:glcummins
ID: 18766696
Okay, I just checked the PHP manual, and '<?=' is a shortcut for '<?php echo '. So, using echo after the '=' will cause problems. I apologize.
0
 
LVL 1

Author Comment

by:pingeyeg
ID: 18766698
I have used it before and it worked, even when I try the other way nothing happens.
0
 
LVL 3

Expert Comment

by:exoska
ID: 18766708
have you tried it with the MYSQL_ASSOC parameter like i d said ?
0
 
LVL 1

Author Comment

by:pingeyeg
ID: 18766722
Not a problem.
0
 
LVL 1

Author Comment

by:pingeyeg
ID: 18766737
When I try that exoska, I get the following error:

Warning: mysql_fetch_array() [function.mysql-fetch-array]: The result type should be either MYSQL_NUM, MYSQL_ASSOC or MYSQL_BOTH. in /Library/WebServer/Documents/address.php on line 316
0
 
LVL 1

Author Comment

by:pingeyeg
ID: 18766781
Where do I place the print_r($_POST); ?
0
 
LVL 3

Accepted Solution

by:
exoska earned 500 total points
ID: 18766835
bottom of the page would be good
but,
i ve realized something
SELECT strProviderservice From tblAdspace WHERE strProviderservice = '".$_POST['request']."'"

buddy, you are requesting the strProviderservice from tblAdspace giving the strProviderservice in the where clause as well. you already got that right? i mean the strProviderservice . it can be the  problem.. maybe something in the query is wrong, it seems so.
0
 
LVL 3

Assisted Solution

by:exoska
exoska earned 500 total points
ID: 18766855
currently you are asking something like select color from colors where color='red'

you might have to request the ID or maybe you are searching for a phrase
i mean strProviderservice field may contain something like "aaabbccc" as a row and request may be "abbbc" so  you  should be querying like

SELECT strProviderservice From tblAdspace WHERE strProviderservice LIKE '%".$_POST['request']."'%"
0
 
LVL 1

Author Comment

by:pingeyeg
ID: 18766873
I see what you are saying.  What I am trying to do is request the hidden value of strProviderservice from the form on the prior page.  That way I can keep carrying that value to the next page.
0
 
LVL 1

Author Comment

by:pingeyeg
ID: 18766902
Man, I feel like an idiot.  The whole time I was thinking that I needed to request the info from the form on the prior page, but what I needed was from the query string.  I got it working now.  Thanks!
0
 
LVL 3

Expert Comment

by:exoska
ID: 18766937
buddy then just use

<input type="hidden" name="strProviderservice" value="<?= $request?>">
<?= $request?>  <----- Not getting anything ot display

if the previous pages form sends the "request" field in the post.
0
 
LVL 3

Expert Comment

by:exoska
ID: 18766981
so, any points to spend ? :)
0

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