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chemical equation - question

Posted on 2007-03-21
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Hello,

i am reading an example and it is given like this :

Silver + Sulfur ---> Ag2S

i understand the second part (Ag2S) . The charge of S =2 etc..
But on the first part Silver has a charge of 1 (correct) but Sulfur has a charge of 6 , +_ 2, 4.
How do i know the charge of the sulfur on the first part ?
Also , i think the equation is not balanced right .
ideas?
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Question by:c_hockland
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by:Infinity08
ID: 18769803
You shouldn't look at this as a balanced equation.

Look at the left side of consisting of an infinite supply of silver (Ag) and Sulfur (S), and the right side as the resulting infinite supply of silver sulfide (Ag2S).

The balanced form would be (as you no doubt know) :

    2 Ag + S --> Ag2S
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Infinity08 earned 500 total points
ID: 18769861
And to answer your question about the charges :

    Ag : charge +1   (Noted as Ag(+) )        <--  oxidation state 1  (the only one)
    S : charge -2   (Noted as S(2-) )            <-- oxidation state -2  (because Ag2S is a sulfide)
    Ag2S : no charge

So :

    2 Ag(+)  +  S(2-)  -->  Ag2S

balances out nicely.
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Author Comment

by:c_hockland
ID: 18769995
ok, i think i got it. Thanks so much.
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