help with session sub array

please explain this.in my php i have


if(isset($_GET['id']))
{
      $_SESSION['a']['b'] = $test->get_test($_GET['id']);
}

dumping this returns...

Array
(
    [1] => Array
        (
            [data] = as expected
            [data] = as expected
            [data] = as expected
           ....
}


for my function to work correctly I need the dump to be at the root so when I var_dump as above it actually looks like this:


Array
(
      [data] = as expected
      [data] = as expected
      [data] = as expected
      [data] = as expected
jimbona27Asked:
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glcumminsCommented:
Perhaps you mean like this:

var_dump($_SESSION['a'])

This will dump the value of $_SESSIOn['a'], which should match the value you expect.
0
jimbona27Author Commented:
tried this.
if(isset($_GET['id']))
{
      $_SESSION['a']['b'] = $package->get_test($_GET['id']);
      _d($_SESSION['a']);
}

and I get this

rray
(
    [data] => Array
        (
            [1] => Array
                (
                    [data]

0
jimbona27Author Commented:
any suggestions?  thanks
0
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jimbona27Author Commented:
heres another example that might help..

var_dump($test_cats);

returns...

Array
(
    [a] => Array
        (
            [1] => hello
            [2] => there
            [3] => today
        )

    [b] => Array
        (
            [5] => another example

...


using this array how can I look through each sub, i.e.


foreach($test_cats as $k=>$v)
{
      echo $k . $v;
}

doesnt work but I want to display..


hello
there
today

thank you.
0
glcumminsCommented:
foreach ($test_cats as $key=>$subarray)
{
      print "<h1>$key</h1>";
      foreach ($subarray as $subkey=>$value)
      {
            print $value . "<br />";
      }
}
0
jimbona27Author Commented:
ok that works great, how can I store each sub array?

$array1 = ('hello','there',''today);
$array2 = (...);
...


thanks
0
glcumminsCommented:
$test_cats['a'] = array('hello', 'there', 'today');
$test_cats['b'] = array('another example');
0
glcumminsCommented:
Or, if the sub-arrays already exist:

$test_cats['a'] = $array1;
$test_cats[b'] = $array2;
0
jimbona27Author Commented:

foreach ($test_cats as $key=>$subarray)
{
    print "<h1>$key</h1>";      
      
    foreach ($subarray as $subkey=>$value)
      {            
              print $value . "<br />";
              
            $test_cats[$key] = $value;
    }      
}

like this?
0
glcumminsCommented:
I guess I am not sure what you are trying to do. The values already exists in $test_cats, so you don't need to set the value there again. Are you trying to create a new array with the values of the sub-array?
0
glcumminsCommented:
<?php

$test_cats = array();
$test_cats['a'] = array('hello', 'there', 'today');
$test_cats['b'] = array('another example');

foreach ($test_cats as $key=>$subarray)
{
      foreach ($subarray as $subkey=>$value)
      {
            if (!isset(${'array_'.$key}))
            {
                  print "Creating variable \$array_$key.<br />";
                  ${'array_'.$key} = array();
            }
            ${'array_'.$key}[] = $value;
      }
}

var_dump($array_a);

print "<br />";

var_dump($array_b);

?>

This creates a dynamic variable for each array. I would not recommend doing this, because dynamic variable names can get messy, but if you must, this method should work.
0
jimbona27Author Commented:
this is the structure as above.

Array
(
    [a] => Array
        (
            [1] => hello
            [2] => there
            [3] => today
        )

    [b] => Array
        (
            [5] => another examplei.e.

........


i need to


getOptions($id)


if I pass 'a' as the parameter

it needs to return

hello
there
today

is that clear?

0
glcumminsCommented:
Why not just this? Just return the entire subarray:

function getOptions($id, $test_cats)
{
      return $test_cats[$id];
}
0

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jimbona27Author Commented:
in this example do I pass

getOptions('a',$test_cat);

doesnt work?

thanks
0
glcumminsCommented:
getOptions('a',$test_cat);

Should be:

getOptions('a',$test_cats);

In the future, rather than "doesn't work", you might provide the actual error message that is given. That will help us resolve the problem in a more timely manner.
0
jimbona27Author Commented:
ok will test it out tomorrow morning as leaving now.  think thats it
0
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