Sum total current month & same last year

Hello,

Here is my sql:

SELECT
StoreID, YEAR(DatePickedUp) AS ROYear,
SUM(BilledHrsNonWarranty + BilledHrsWarranty + BilledHrsStock) as TotalHours,
SUM(PartsAmtNonWarranty + PartsAmtWarranty + PartsAmtStock) as TotalParts,
SUM(SubletAmtNonWarranty + SubletAmtWarranty + SubletAmtStock) as TotalSublet,
SUM(LaborAmtNonWarranty +  LaborAmtWarranty +  LaborAmtStock) as TotalLabor,
COUNT(RONumber) AS ROCount, SUM(Deposit1 + Deposit2 + Deposit3 + Deposit4 + PaymentAmt1 + PaymentAmt2 + PaymentAmt3) AS TotalROAmount

FROM
ROSummary

WHERE Year(DatePickedUp) BETWEEN 2006 And 2007
GROUP BY
StoreID, YEAR(DatePickedUP)

I'm trying to get the total labor for the current month and current month 1 year ago.
This is being used in SQL 2005 reporting services.

Thanks

Dan
DanPerlmanAsked:
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chrismcCommented:
Group by month and in the where, just choose this month and the month 1 year ago.

Where (Year(GetDate()) = Year(DatePickedUp) Or Year(GetDate())-1 = Year(DatePickedUp)) And Month(GetDate()) = Month(DatePickedUp))

Cheers
Chris
0
JimyLeeCommented:
If you are trying to get the previous year's total in the same result row as this year's data, something like this may do the trick for you.

SELECT
StoreID, YEAR(DatePickedUp) AS ROYear,
SUM(BilledHrsNonWarranty + BilledHrsWarranty + BilledHrsStock) as TotalHours,
SUM(PartsAmtNonWarranty + PartsAmtWarranty + PartsAmtStock) as TotalParts,
SUM(SubletAmtNonWarranty + SubletAmtWarranty + SubletAmtStock) as TotalSublet,
SUM(LaborAmtNonWarranty +  LaborAmtWarranty +  LaborAmtStock) as TotalLabor,
(select SUM(LaborAmtNonWarranty +  LaborAmtWarranty +  LaborAmtStock) from ROSummary where year(DatePickedUp) = 2006 and StoreID = ROS.StoreID) PrevYearTotalLabor
COUNT(RONumber) AS ROCount, SUM(Deposit1 + Deposit2 + Deposit3 + Deposit4 + PaymentAmt1 + PaymentAmt2 + PaymentAmt3) AS TotalROAmount
FROM ROSummary ROS
WHERE Year(DatePickedUp) = 2007
GROUP BY StoreID, YEAR(DatePickedUP)

Hope I didn't leave out anything in there.  Not at my normal computer today.  Hope it helps.

JimyLee
0

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Microsoft SQL Server 2005

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