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2sodium + iodine ---> 2NaI

Posted on 2007-03-22
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Last Modified: 2007-12-19
Hi , i am studying a chemistry example and i read this :

2sodium + iodine ---> 2NaI

i understand the chemical addition here. But why do i need the ( 2) on both sides of equations ?

the electrical charge of Na = 1 and so is Iodine's.

I have several examples like that and i cant figure out how do they come up with these charges .
any ideas ?
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Question by:c_hockland
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10 Comments
 
LVL 53

Expert Comment

by:Infinity08
ID: 18775519
That should be :

    2 Na + I2 ---> 2 NaI

sodium (Na) with iodine (I2) forms sodium iodide (NaI)
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Assisted Solution

by:KelvinY
KelvinY earned 400 total points
ID: 18775750
Iodine atoms do not exist in isolation. Iodine forms molecules of I2 by covalent bonding. Since a molecule of I2 is the smallest unit that free iodine can exist as it is the base unit for any chemical equation involving iodine. So Infinity08's equation is spot on.
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Expert Comment

by:dragonjim
ID: 18776150
Na + I2 ----> NaI

to balance properly, you need 2 Iodines on the products side:

Na + I2 ---> 2NaI

you now need to balance the Sodium.

2Na +I2 ---> 2NaI

FYI -- in I2, the 2 is a subscript indicating 2 iodine.
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LVL 10

Expert Comment

by:dragonjim
ID: 18776176
Also -- must you verify the electrical charges balance... above we only showed the chemicals balance.

(to balance the charges) take each charge, multiple by the number  present.

2Na(1+) + I2(1-) --> 2NaI(no charge)
(2*1) + (2*-1) = (2*0)
2 + -2 = 0
0 = 0

balanced.
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Author Comment

by:c_hockland
ID: 18779414
i guess my question is how am i suppose to know which ones comes on pair like iodine and which ones are not (especially when i am given words instaed of symbols)

any ideas ?
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LVL 53

Assisted Solution

by:Infinity08
Infinity08 earned 400 total points
ID: 18779508
You can look it up :)

iodine is a halogen (check the periodic table), and the elemental form of halogens is always as diatomic molecules (ie. I2 in the case of iodine).

sodium however is an alkali metal (check the periodic table). In nature it doesn't occur very much in its elemental form.
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Accepted Solution

by:
dragonjim earned 1200 total points
ID: 18779534
Seeing as this is either HS Chem or Freshman Chem... its largely memorizing / recognizing.
The paired / multiple atoms to a molecule comes from electron stability (Sulfur can exist as S8).

Largely, the 6A & 7A series.

Hydrogen
Nitrogen
Oxygen
Fluorine
Chlorine
Bromine
Iodine
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Author Comment

by:c_hockland
ID: 18779538
that was great!! thanks so much
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by:dragonjim
ID: 18779575
Infinity08 -- I'm assuming this is for a course (either HS or Freshman College). In which case, C_Hockland may be required to identify the diatomic / etc on a quiz / test.

The ones you'll likely see on any such test, I listed above. As Infinity said, the Halogen (7A) always exist as diatomic. Other than that, the ones you see are the liquid / gas elements near the 7A.

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LVL 53

Expert Comment

by:Infinity08
ID: 18779615
>> In which case, C_Hockland may be required to identify the diatomic / etc on a quiz / test.
Then my answer still stands : in order to know how different elements behave, and what their elemental forms are, the periodic table is "the bible". Just check it - it contains all information you'll need for this kind of stuff.
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