Unix Sorting Challenge

Here's a sorting challenge.  You can use Unix sort command or Perl/awk.  Price to the most succinct answer.

Given the following input file:

fx_act1_r-2006-04-29.lis,1
fx_act2_r-2006-04-29.lis,1
fx_act1_r-2006-04-26.lis,10
fx_act1_r-2006-04-26.lis,11
fx_act1_r-2006-04-26.lis,9
fx_act1_r-2006-04-27.lis,10
fx_act1_r-2006-04-27.lis,28
fx_act1_r-2006-04-27.lis,8
fx_act1_r-2006-04-27.lis,9
fx_act1_r-2006-04-28.lis,10
fx_act1_r-2006-04-28.lis,11
fx_act1_r-2006-05-01.lis,21
fx_act1_r-2006-05-01.lis,22
fx_act2_r-2006-04-26.lis,10
fx_act2_r-2006-04-26.lis,11

the file needs to be sorted alphabetically by filename (eg: fx_act1_r), then by date (eg: 2006-04-27), then by sequence number suffix (eg: 11)

So for the above input, the sorted output would be:

fx_act1_r-2006-04-26.lis,9
fx_act1_r-2006-04-26.lis,10
fx_act1_r-2006-04-26.lis,11
fx_act1_r-2006-04-27.lis,8
fx_act1_r-2006-04-27.lis,9
fx_act1_r-2006-04-27.lis,10
fx_act1_r-2006-04-27.lis,28
fx_act1_r-2006-04-28.lis,10
fx_act1_r-2006-04-28.lis,11
fx_act1_r-2006-04-29.lis,1
fx_act1_r-2006-05-01.lis,21
fx_act1_r-2006-05-01.lis,22
fx_act2_r-2006-04-26.lis,10
fx_act2_r-2006-04-26.lis,11
fx_act2_r-2006-04-29.lis,1


Be creative!
LVL 48
TintinAsked:
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ozoCommented:
perl -e 'print map/\0(.*)/s,sort map{sprintf"%s%9d\0%s",(/((.*,)(\d+)\s*)/)[1,2,0]}<>' file
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gheistCommented:
Using GNU sort from their coreutils, as written in /etc/passwd example at "info coreutils sort" info page:

sort -t, -k1b,1 -k2,2n
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tfewsterCommented:
gheist, you could shorten your answer to
sort -t, -k1,1 -k2n

I never thought of treating name+date as one "field", so I came up with this:
sed 's/-\([0-9][0-9]*\)/,\1/' file|sort -t, -k1,1 -k2,2 -k3n|sed 's/,\([0-9][0-9]*\)/-\1/'
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gheistCommented:
One can use two "sort" commandswith differentseparators, assuming undocumented feature to keep tails after comma sorted after resorting against date.
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TintinAuthor Commented:
All very good solutions, but I always like the simplest solution.    As usual, ozo comes up with a great Perl one liner.
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