Error in sql syntax

What seems to be wrong with this sql statement?

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1

$strSQL_Delete = mysql_query("DELETE FROM tblReviews WHERE strCompanyname = '" . $_POST['strCompanyname'] . "' and reviewID =" . $_POST['reviewID']) or die(mysql_error());
LVL 1
pingeyegAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

glcumminsCommented:
When you encounter errors like this, it helps to see the entire SQL statement as it is submitted, rather than with the variables in place. Try this modification to your code:

$query = "DELETE FROM tblReviews WHERE strCompanyname = '" . $_POST['strCompanyname'] . "' AND reviewID =" . $_POST['reviewID'];
$strSQL_Delete = mysql_query($query) or die ("The following query failed: $query. <br /> The MySQL error was: " . mysql_error());

This seperates the query string from the mysql_query statement so that we can see exactly what is being submitted. There is a possibility that one of the $_POST variables you are submitting has an errant quote in it.
0
Cornelia YoderArtistCommented:
"
DELETE FROM tblReviews WHERE strCompanyname =
'
"
 . $_POST['strCompanyname'] .
"
'
and
reviewID =
"
 . $_POST['reviewID']

I've separated out where you have single and double quotes mixed together.  As you can see, the structure doesn't make sense.  What you probably mean to do is

"DELETE FROM tblReviews WHERE strCompanyname = " . $_POST['strCompanyname'] . " and reviewID =" . $_POST['reviewID']

It would be much easier for you if you would use the syntax

$sqlquery = "DELETE FROM tblReviews WHERE strCompanyname = " . $_POST['strCompanyname'] . " and reviewID =" . $_POST['reviewID'];

$strSQL_Delete = mysql_query($sqlquery) or die(mysql_error());


0
Cornelia YoderArtistCommented:
Oops, you do need the single quotes also:

$sqlquery = "DELETE FROM tblReviews WHERE strCompanyname = '" . $_POST['strCompanyname']' " . " and reviewID =" . $_POST['reviewID'];
0
Exploring SharePoint 2016

Explore SharePoint 2016, the web-based, collaborative platform that integrates with Microsoft Office to provide intranets, secure document management, and collaboration so you can develop your online and offline capabilities.

pingeyegAuthor Commented:
Either way I code it, I still get the same error message.
0
pingeyegAuthor Commented:
I know that.  I kept them in.  Thanks though.
0
glcumminsCommented:
@yodercm:

 strCompanyname = ' " . $_POST['strCompanyname']' "

This will result in mis-matched singe quotes. You have the first single quote inside the double-quoted string, but the second occurs outside of it. pingeyeg had it correct the first time, as far as I can tell.
0
pingeyegAuthor Commented:
This is what I have right now, but like I said I get the same error message:

$strSQL_Delete = "DELETE FROM tblReviews WHERE strCompanyname = '" . $_POST['strCompanyname'] . "' and reviewID =" . $_POST['reviewID'];
$SQL = mysql_query($strSQL_Delete) or die(mysql_error());
0
glcumminsCommented:
Change:

$SQL = mysql_query($strSQL_Delete) or die(mysql_error());

to:

$strSQL_Delete = mysql_query($query) or die ("The following query failed: $query. <br /> The MySQL error was: " . mysql_error());

so that we can see the entire SQL query as it is submitted to the server. We don't currently know what is contained in '$_POST['strCompanyname']' and '$_POST['reviewID']', so we cannot accurately troubleshoot the statement.
0
glcumminsCommented:
Or rather:

$SQL = mysql_query($strSQL_Delete) or die ("The following query failed: $strSQL_Delete. <br /> The MySQL error was: " . mysql_error());

(Sorry, I had the variable names wrong the first time).
0
pingeyegAuthor Commented:
Not sure why I am not getting the values from the variables, but this is my result:

The following query failed: DELETE FROM tblReviews WHERE strCompanyname = '' and reviewID =.
The MySQL error was: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1
0
glcumminsCommented:
Do you want us to take a look at that part of the code, or will you troubleshoot that?

Make sure that the form that posts the data is using 'method="POST"', and that the field names are correct.
0
Cornelia YoderArtistCommented:
Ok, the best solution is to clean up the messy query!

First of all, you should NEVER use a $_POST directly in a query.  It leaves you WIDE OPEN to SQL Injection hacking.  So do this:

$inputcompanyname = htmlentities($_POST['strCompanyname'],ENT_QUOTES);
$inputreviewID = htmlentities($_POST['reviewID'],ENT_QUOTES);

$strSQL_Delete = "DELETE FROM tblReviews WHERE strCompanyname = '$inputcompanyname' and reviewID = '$inputreviewID' ";

$SQL = mysql_query($strSQL_Delete) or die(mysql_error());
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
pingeyegAuthor Commented:
Ok, I'm no longer getting an error, but the requested review isn't being deleted either.
0
pingeyegAuthor Commented:
Ok, right now I got the company to show, but the reviewID is showing as reviewID instead of a number when displaying the sql statement.

DELETE FROM tblReviews WHERE strCompanyname = 'Plumbing When You Need It' and reviewID = 'reviewID'
0
Cornelia YoderArtistCommented:
$inputcompanyname = htmlentities($_POST['strCompanyname'],ENT_QUOTES);
$inputreviewID = htmlentities($_POST['reviewID'],ENT_QUOTES);

echo "input company name = $inputcompanyname <br>";
echo "input review ID = $inputreviewID <br>";

See if the values are correct.
0
pingeyegAuthor Commented:
Nope:

input company name = Plumbing When You Need It
input review ID = reviewID
0
Cornelia YoderArtistCommented:
So, you are getting the string "reviewID" instead of the correct ID number.  Fix that in your form input.
0
pingeyegAuthor Commented:
Nevermind, I got it.  Thanks!
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
PHP

From novice to tech pro — start learning today.