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PI in c

#include <stdio.h>
#include <math.h>

void main()
            float PI= 4.0*atan(1.0);
            float x = PI;

----> it works. However, i tried
float  PI=(float)  M_P instead of  float PI= 4.0*atan(1.0);
---> doen'st work.

 Please help me . Thanks
PS: i use visual c++ 6.0
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5 Solutions
what is M_P?

and also it is a good practice to use float PI=static_cast<float>(M_P)

hi it is M_PI not M_P

u have to define _USE_MATH_DEFINES using
to get use of math definitions for common math constants

or you have to include _USE_MATH_DEFINES in the compiler settings, where we set external macros

if not working try below

acctually atan will uses double as input and double as output, better use atanf for floating point values

#ifndef M_PI
#define M_PI 3.14159265358979323846 /* pi */
>>>> it is a good practice to use float PI=static_cast<float>(M_P)
You don't need a cast at all. If you need a better precisiuon use a double instead of a float.

>>>> float PI= 4.0*atan(1.0);
As PI is a constant you should avoid to compute it by using trigonometric functions.

Regards, Alex

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>>As PI is a constant you should avoid to compute it by using trigonometric functions.

It is one of the many definitions of PI in mathematics where PI is derived from.

>> It is one of the many definitions of PI in mathematics where PI is derived from.

The problem is that the atan() function probably makes use of PI to calculate the result (directly or indirectly). So, you've got a recursive definition, which is not good :)

>> float  PI=(float)  M_P instead of  float PI= 4.0*atan(1.0);
>> ---> doen'st work.

How does it not work ? What result do you get ? If M_PI is defined like this :

#define M_PI 3.14159265358979323846 /* pi */

then there shouldn't be a problem.
>>>> It is one of the many definitions of PI in mathematics
>>>> where PI is derived from.
No, PI is not derived it is a constant. You can get PI as a result of many mathematical algorithms or by calculating infinite rows, however that is like you would calulate 2.0 by sum(1 + 1/2 + 1/4 + 1/8 + ...) what gives the correct result but nevertheless is nonsense.
>>No, PI is not derived it is a constant.

It is indeed a constant where the value is derived by many mathematical methods.

I agree that in programming instead of derivation using the constant value will definitely make more sense.
very funny C and static_cast<float>(

using the proper constans is the correct answer IMHO or if you need more precision checking the diverse large rational packages.

sometimes when you need more precision you can calculate the method of PI by algorithms, say like you want a precision even greater than double, or double in x64 architectures, and pi isnt well enogh define (PI has infinite number not equal 0 after the . ) for your purpose then you should calculate it. but normally the trigonometric functions already use a constant  (math.h is your friend), calculating something which is already calculated may cause loss of precision and time. You can calculate PI by:
4*(1-(1/3)+(1/5)-(1/7)+(1/9)- ...)= M_PI
When I used to work on 16 bit machines, 355.0 / 113.0 was a pretty good approximation - better than 22/7 which was only accurate to 2 DP.  

This should be a compile time thing so I'd declare it as

const double PI = 355.0 / 113.0;  /* the pattern is 11 33 55 written from bottom to top */

or if you want something more accurate (from http://en.wikipedia.org/wiki/Pi)

const double PI = 3.14159265358979323846264338327950288419716939937510;

const basically means "I promise not to change it".  It is better than using #defines - if you get it wrong, you can change it in the debugger (OK - I broke my promise but I was debugging) and keep on testing instead of having to stop and rebuild.
>>>>> const double PI = 3.14159265358979323846264338327950288419716939937510;
As a double on a 32bit platform has a maximum precision of about 15 significant decimal digits you may not worry if you have a typo when copying the above number ;-)
Cut and paste is your friend :)
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