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style.display = "table-row" - IE6 error


This does not work with IE6 (it gives an error)
         new_value = "table-row";
         document.getElementById("pageHeader").style.display = new_value;

And looks very poorly formated in FF:
         new_value = "block";
         document.getElementById("pageHeader").style.display = new_value;

Any ideas?
2 Solutions
Yury MerezhkovDevelopment Team LeadCommented:
I use this function to show/hide TR. Check it out. Works nicely for me in both FF and IE 6/7:

function showHide() {
      var tr = document.getElementById("Your_Element_Id_Here");
      var trVisible;
      if(navigator.appName.indexOf("Microsoft") > -1)
            trVisible = "block"
            trVisible = "table-row"
      if (tr.style.display == "none")
            tr.style.display = trVisible
            tr.style.display = "none"
Why don't you just use  ''  (an empty string) instead of "block" or "table-row"? Then each browser will reset style.display to it's defaulr value (which may be "block" or "table-row" depending on the browser engine).
So simply toggle the display value between   'none'   and   ''.
An empty string may not work if "none" is set for display property in a CSS style sheet.

Setting display to "" will reset only element's inline style display value. If some CSS rule applies to the element, then resetting the inline value will enable that CSS rule. If it was defined so that the element is not to be displayed, then switching between 'none' and '' will give no result (the element will remain hidden).
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