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SAX, DOM or Xpath

hi I wrote this code to set a flage if the elment data is "XML" and to print the data of the second elemnt but it did not work
so I do not know waht is the elements name I only know that if I find" XML"as data in one of the elemnts then I have to print the data in the next element???
 
package com.psol.xbe2;
import java.io.FileReader;
import java.lang.String;

import org.xml.sax.XMLReader;
import org.xml.sax.Attributes;
import org.xml.sax.InputSource;
import org.xml.sax.helpers.XMLReaderFactory;
import org.xml.sax.helpers.DefaultHandler;


public class MySAXApp1 extends DefaultHandler
{
      private boolean isOracle = false;

    public static void main (String args[])
      throws Exception
    {
      XMLReader xr = XMLReaderFactory.createXMLReader();
      MySAXApp1 handler = new MySAXApp1();
      xr.setContentHandler(handler);
      xr.setErrorHandler(handler);

                        // Parse each file provided on the
                        // command line.
      for (int i = 0; i < args.length; i++) {
          FileReader r = new FileReader(args[i]);
          xr.parse(new InputSource(r));
      }
    }


    public MySAXApp1 ()
    {
      super();
    }


    ////////////////////////////////////////////////////////////////////
    // Event handlers.
    ////////////////////////////////////////////////////////////////////


    public void startDocument ()
    {
      System.out.println("Start document");
    }


    public void endDocument ()
    {
      System.out.println("End document");
    }


    public void startElement (String uri, String name,
                        String qName, Attributes atts)
    {
      //if ("".equals (uri))
      //    System.out.println("Start element: " + qName);
      //else
         // System.out.println("Start element: {" + uri + "}" + name);
    }


    public void endElement (String uri, String name, String qName)
    {
      // if ("".equals (uri))
        //  System.out.println("End element: " + qName);
      //else
        //  System.out.println("End element:   {" + uri + "}" + name);
    }


    public void characters (char ch[], int start, int length)
    {
    String a;
 
   
      //System.out.print("Characters:    \"");

            a= String.valueOf (ch, start,length);
            
            if (isOracle)
            {
            System.out.print("yyy"+ a+ "yyy");
            isOracle = false;

            }
            
             if (a.equals("XML"))
             {
System.out.print("XXXX"+ a+ "XXXX");
isOracle = true;}

      //System.out.print("\"\n");
          }
    }

The XML document
<?xml version = '1.0' encoding = 'UTF-8'?>
   <catalog>
     <journal>
       <journal_title>Open:</journal_title>
       <publisher>Oracle Publishing</publisher>
       <edition>Sept-Oct 2003</edition>
       <article_section>XML</article_section>
       <title>Parsing XML Efficiently</title>
       <author>Julie Basu</author>
    </journal>
    <journal>
      <journal_title>Oracle Magazine</journal_title>
      <publisher>Oracle Publishing</publisher>
      <edition>Nov-Dec 2003</edition>
      <article_section>SQL</article_section>
      <title>The Active Database</title>
      <author> Cameron ORourke </author>
    </journal>
   </catalog>
0
badour_ma
Asked:
badour_ma
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1 Solution
 
ADSLMarkCommented:
This works:

package com.psol.xbe2;

import java.io.*;

import org.xml.sax.*;
import org.xml.sax.helpers.*;

public class MySAXApp1
    extends DefaultHandler
{
    private boolean foundXML;
    private boolean insideTag;

    public MySAXApp1()
    {
        this.foundXML = false;
        this.insideTag = false;
    }

    public void startElement(String uri, String name, String qName, Attributes atts)
    {
        this.insideTag = true;
    }

    public void endElement(String uri, String name, String qName)
    {
        this.insideTag = false;
    }

    public void characters(char ch[], int start, int length)
    {
        String data = String.valueOf(ch, start, length);

        if(this.insideTag && this.foundXML)
        {
            System.out.print("Data in next tag after founding 'XML': "+data);
            this.foundXML = false;
        }

        if(data.equals("XML"))
            this.foundXML = true;
    }

    //Program entry
    public static void main (String args[])
        throws Exception
    {
        MySAXApp1 handler = new MySAXApp1();

        // Create xml reader
        XMLReader xr = XMLReaderFactory.createXMLReader();
        xr.setContentHandler(handler);
        xr.setErrorHandler(handler);

        // Parse each file provided on the command line.
        for(int i=0;i<args.length;i++)
            xr.parse(new InputSource(new FileReader(args[i])));
    }
}

You forgot to check whether you were inside an element yes/no. Now that i've added that boolean flag, it only reads the content when inside a tag. Previous you would be reading whitespace after the tags.

Mark
0
 
Mayank SAssociate Director - Product EngineeringCommented:
So what has to do with: >> SAX, DOM or Xpath
0
 
badour_maAuthor Commented:
thanks alot ADSLMark
0
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badour_maAuthor Commented:
hi mayankeagle:
I did my code using SAX parser, So In order to get my request to I have to change it to DOM parser or to use xpath
0
 
badour_maAuthor Commented:
I am facing another problem:(
I wnat to search for 15 data in one XML doucemnt !!!
ex.
XML
Java
c
c++
...
...
so it is not logical to use 15 flag!!!
what can I do???
0
 
ADSLMarkCommented:
If you want to remember which tag you were looking for, then you could save the tag data in a String variable and use the boolean flag to signal that the previous value was interesting (and if you want to know what, print the string variable), so please get me the next value inside the upcoming tag.
So basically you only have to alter the:

if(data.equals("XML"))
    this.foundXML = true;

into sth which searches for all the strings:

if("XML".equals(data) || "HTML".equals(data) || ...)
{
    this.foundXML = true;
    this.prevValue = data;
}

Mark
0
 
badour_maAuthor Commented:
again thank u
u seem so smart so can you please help me coz I am facing alot of problrms??
0
 
ADSLMarkCommented:
Heh, sure I can help, but I have to go now, so I don't have time now. Anyway, there are enough people around to answer all your questions and if not I will answer them when I come back.

Mark
0
 
Mayank SAssociate Director - Product EngineeringCommented:
>> So In order to get my request to I have to change it to DOM parser or to use xpath

http://java.sun.com/webservices/jaxp/dist/1.1/docs/tutorial/dom/1_read.html
0

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