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Convert Timestamp String to Regular Date & Time Format in ASP Classic

Posted on 2007-03-30
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Last Modified: 2008-01-09
In ASP 3 with VB Script, how do I convert a timestamp string like
     2007-03-29  17:30:21    

to standard date format like
     03-29-2007  05:30 PM  ?

For example, in PHP I could do:

     $string = "2007-03-29  17:30:21";
     $updated = date('m-d-Y h:i A', strtotime($string) );

What is the ASP equivalent?  Thanks.
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Question by:Randall-B
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6 Comments
 
LVL 51

Expert Comment

by:Ryan Chong
ID: 18827458
try

<%
      str = "2007-03-29  17:30:21"
      
      strDate = cDate(str)
      newstr = right("0" & month(strDate),2) & "-" & right("0" & day(strDate),2) & "-" & right("00" & year(strDate),4) & " " & right("0" & hour(strDate),2) & ":" & right("0" & minute(strDate),2) & " "
      if hour(strDate) > 12 then
            newstr = newstr & "PM"
      else
            newstr = newstr & "AM"
      end if
      
      response.write str & " to " & newstr
%>
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LVL 75

Expert Comment

by:Anthony Perkins
ID: 18828953
Or if you like living dangerously you can depend on the computer settings as in:

MsgBox FormatDateTime(CDate("2007-03-29  17:30:21"), vbGeneralDate)
0
 

Author Comment

by:Randall-B
ID: 18830871
ryancys,
   Thanks; that works great except it is not converting "17" to "05" in "17:30:21".  I would like it to output:   03-29-2007  05:30 PM  (with the "05"). Thanks.

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Author Comment

by:Randall-B
ID: 18830876
acperkins,
   Thanks for the alternate suggestion. As you noted, depending on the computer settings might be risky, as each user could different settings, so I'll go with the method ryancys suggested. Thanks again.
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LVL 51

Accepted Solution

by:
Ryan Chong earned 250 total points
ID: 18830955
oops, sorry, try this instead:


<%
      str = "2007-03-29  17:30:21"
     
      strDate = cDate(str)
     
   if hour(strDate) = 12 then  

 newstr = right("0" & month(strDate),2) & "-" & right("0" & day(strDate),2) & "-" & right("00" & year(strDate),4) & " " & right("0" & hour(strDate),2) & ":" & right("0" & minute(strDate),2) & " PM"

    elseif hour(strDate) > 12 then

 newstr = right("0" & month(strDate),2) & "-" & right("0" & day(strDate),2) & "-" & right("00" & year(strDate),4) & " " & right("0" & hour(strDate)-12,2) & ":" & right("0" & minute(strDate),2) & " PM"

      else

 newstr = right("0" & month(strDate),2) & "-" & right("0" & day(strDate),2) & "-" & right("00" & year(strDate),4) & " " & right("0" & hour(strDate),2) & ":" & right("0" & minute(strDate),2) & " AM"

      end if
     
      response.write str & " to " & newstr
%>
0
 

Author Comment

by:Randall-B
ID: 18830980
ryancys,
   That's it. Thanks!
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