passign values from database to textbox with php/mysql

Posted on 2007-04-01
Last Modified: 2013-12-12
I am trying to build an update page,
I have problem in getting the vaules from the database into a textboxes so the user can see the old values,
it is my first time to do this so I don't know how:
This is my code:


$query=" SELECT * FROM Companies WHERE Company_id='1'";
while ($i < $num) {




<title>Update Page</title>

<form action="updated.php" method="post">

Compnay_id <input type="text" name="ud_first" value="<? echo $Company_id; ?>"><br>
Company_name <input type="text" name="ud_last" value="<? echo $Company_name; ?>"><br>
City <input type="text" name="ud_phone" value="<? echo $City; ?>"><br>
State <input type="text" name="ud_mobile" value="<? echo $State; ?>"><br>
<input type="Submit" value="Update">

This did not work with me and don't stuck with this code, if you have better ideas or easier code it would be great,

Thank you

Question by:amer_net
  • 2
  • 2
LVL 35

Expert Comment

ID: 18833524
The problem is that mysql_numrows should have an additonal _ and that to pull rhte result values you need to use something like $row = mysql_fetch_array or mysql_fetch_assoc with the $result,

also you may want to use full tags for your echoing into your text values

Author Comment

ID: 18833595
can you give me any example
forget about my code because I took it from the internet and i did not understand it very well,
I want any example in which I can take the values from my database into the textbox,
use only one text box thats fine.

thank you
LVL 35

Accepted Solution

Raynard7 earned 500 total points
ID: 18833688
Hi, I have unashamedly modified the excellent example for mysql_fetch_assoc from the php site,
note that this should retreive your data put them into values then output - I have not tested the form but the idea is there
now - if you do not have short tags enabled <? may not work - so I have used <?= which may be used as a shortcut for <?php echo the others use the unabbreviated form - which may be the only one that works.


$conn = mysql_connect("localhost", "mysql_user", "mysql_password");

if (!$conn) {
    echo "Unable to connect to DB: " . mysql_error();
if (!mysql_select_db("mydbname")) {
    echo "Unable to select mydbname: " . mysql_error();

$sql = "SELECT * FROM Companies WHERE Company_id='1'";

$result = mysql_query($sql);

if (!$result) {
    echo "Could not successfully run query ($sql) from DB: " . mysql_error();

if (mysql_num_rows($result) == 0) {
    echo "No rows found, nothing to print so am exiting";

// While a row of data exists, put that row in $row as an associative array
// Note: If you're expecting just one row, no need to use a loop
// Note: If you put extract($row); inside the following loop, you'll
//       then create $userid, $fullname, and $userstatus
while ($row = mysql_fetch_assoc($result)) {
    $Company_id = $row["Company_id"];
    $Company_name = $row["Company_name"];
      $City = $row["City"];
      $State = $row["State"];





<title>Update Page</title>

<form action="updated.php" method="post">

Compnay_id <input type="text" name="ud_first" value="<?=$Company_id; ?>"><br>
Company_name <input type="text" name="ud_last" value="<?php echo $Company_name; ?>"><br>
City <input type="text" name="ud_phone" value="<?php echo $City; ?>"><br>
State <input type="text" name="ud_mobile" value="<?php echo $State; ?>"><br>
<input type="Submit" value="Update">

Author Comment

ID: 18833715
Thank you so much

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