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VbScript solution... Query partition mount points on Windows 2000?

Posted on 2007-04-02
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Last Modified: 2013-11-30
I am currently using the WMI to query partition information about the local drive, but am struggling to find a way to get the Mount Point of a partition if it doesn't have a drive letter assigned.

It appears that there are 3 main WMI classes that deal with local drive partitions...
Win32_DiskPartition
Win32_LogicalDisk
Win32_LogicalDiskToPartition

The only class to return free space information is LogicalDiskToPartition, but this doesn't detect partitions that aren't assigned a drive letter.

We have partitions that have mount points instead of drive letters, and i need to interrogate these. Does anyone have any information regarding any other classes or methods i could use to loop through each partition on a machine taking free space, mount path (or driver letter) and volume name information as i go?

There is a Win32_Volume and Win32_MountPoint class in Windows 2003 and later... why did they wait this long to release them!?

Any help will be much appreciated.

Thanks,
Dez
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Question by:DjDezmond
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4 Comments
 
LVL 63

Expert Comment

by:SysExpert
ID: 18839087
Isn't the info available in the Disk manager ?

If so, you should be able to access it somehow.

Other option is to run a batch file that simply does a DIR
of each partition to a text file, and pull the info out.

I hope this helps !
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by:DjDezmond
ID: 18843286
Thanks, but that wouldn't work as some of the partitions might be hidden, or without drive letters.

I think i just have to except that i wont be able to programmatically do this without using 3rd party tools.
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Accepted Solution

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SysExpert earned 1000 total points
ID: 18843993
See if Winmsd recognizes all partitions, and gives you the info you need.

You should be able to extract data from the text file export.

I hope this helps !
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LVL 9

Author Comment

by:DjDezmond
ID: 18849491
Yea ive used PQDisk to log a simple show command... im now splitting the log file up to extract the info i need... seems to be doing the trick.

Ill accept your solution, although it wasn't what i did in the end... but thanks for your help all the same!

Dez
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