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pass array as literal to method

Posted on 2007-04-03
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Last Modified: 2013-11-23
Hi,
I have a constructor which accepts an array as an argument.
I want to create a new instance of the object and pass it some literal values for the array, but I cant seem to find the correct syntax for this. Can anyone help?
As an example:
private static int [] DOB = new int[2];
public Object(String name, int [] DOB)
       {
      etc..
       }

Object person= new Object("Bart", {12,05});
So this would create a new object whose name is bart and date of birth 12th of May.
Unfortunately this wouldnt compile as I could not pass the array like this.

Cheers
John
0
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Question by:jdav3579
  • 2
3 Comments
 
LVL 16

Accepted Solution

by:
imladris earned 125 total points
ID: 18845171
The syntax you propose is reasonable; unfortunately it is not supported. You'll have to do the obvious instead:

int [] dob={12, 5 };
Object person=new Object("Bart",dob);

Or, of course, you could create an alternate constructor that takes two ints instead:

public Object(String, name,int day,int month)
{    ...
}

then you could call it with:

Object person=new Object("Bart",12,5);
0
 
LVL 16

Expert Comment

by:imladris
ID: 18851271
Did that help?

If so it is now time to grade the answer.

If not, perhaps a clarifying question would help.
0
 

Author Comment

by:jdav3579
ID: 18852559
Hi imladris,
I have only just had a chance to try it - but yes it did help thanks.
John
0

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