Regular expression.

[0-9]{6}

YYYYMM
200400
The expression above excepts  200400
We must not let it accept it.
mathieu_cuprykAsked:
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mrichmonCommented:
([12][0-9]{3})(0[1-9]|1[0-2])

which allows the year to start with 1 or 2 followed by 3 digits, then the month syould be 01 upto 09 or 10 through 12
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mrichmonCommented:
Also if you are using a language or parser that returns parenthesized substring matches, you will get the year in the first substring match and the month in the second.
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