Convert ColorDialog control colors to ARGB and color type questions

I am allowing the user to select a new background color for a label control via the ColorDialog control.
They can pick any background color they like.
However, the label text color is Black, so certain background colors will make the label text illegible (as some would for any given text color.)
So, I would like to automatically change the color of the text to a legible color based on the user's background color choice to make it "impossible" to obscure the label text.

This is for a windows program, but I am going to use some formulas from the W3C that calculate the color and brightness contrast between two RGB color values.
(Source: http://www.w3.org/TR/2000/WD-AERT-20000426)
>>>>>>>>>>
Color brightness is determined by the following formula:
((Red value X 299) + (Green value X 587) + (Blue value X 114)) / 1000
Note: This algorithm is taken from a formula for converting RGB values to YIQ values. This brightness value gives a perceived brightness for a color.

Color difference is determined by the following formula:
(maximum (Red value 1, Red value 2) - minimum (Red value 1, Red value 2)) + (maximum (Green value 1, Green value 2) - minimum (Green value 1, Green value 2)) + (maximum (Blue value 1, Blue value 2) - minimum (Blue value 1, Blue value 2))
<<<<<<<<

According to their page, the color brightness difference should be about 125, the color difference should be about 500 so I will use their values.

Here's what I think I need to do:
1. Take the user's color selection from the ColorDialog control
2. If necessary, convert the color value from ColorDialog control to the appropriate type for the next step.
3. Break it into ARGB values
4. Use those values and the values for Black (label text color) in the formula
5. Make sure the brightness values differ by at least 125 and the color differences by at least 500.
6. Do any necessary color value or type conversions back to the right VB.net color type for the next step.
7. Set the label's text color to the new value.

I am getting stuck at 2. and 3 (which implies I will get stuck at 6.)

What "type" does the colordialog control return and what other type do I need to convert it to in order to get RBG values?

What generally do I need to know about VB.net color types?

Thank you.


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bobinorlandoAsked:
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dctuckConnect With a Mentor Commented:
The colordialog returns a Color type. You can then use:

colorDialog1.Color.R
colorDialog1.Color.G
colorDialog1.Color.B

to extract the R,G, Bvalues of the selected color returned by the ColorDialog
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