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Access 2002 Query to obtain Octet values from an IP Address field

Posted on 2007-04-05
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Last Modified: 2011-09-20
Is there a way in Access 2002 Query to split an IP Address into octets?  if [IP_Address} contains   192.168.10.1
So the result would show new columns as below
[A] = 192  [B] = 168   [C] = 10

Many thanks
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Question by:westermo
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4 Comments
 
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Accepted Solution

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rockiroads earned 500 total points
ID: 18857093
if its fixed positions then u can use a combination of left and mid

or u can create a vba function if u cannot guarantee it being in the same pos
eg


public function GetPartIP(byval sIP as String, byval iOctet as integer) as String

    dim sVals() as String

    sVals = split(sIP,".")
    GetPartIP = sVals(iOctet-1)
end function

then in your query u would do

select GetpartIP(myipfield,1) as FirstNode, GetPartIP(myipfield,2) AS SecondNode, GetPartIP(myipfield,3) as thirdNode
from mytable
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Expert Comment

by:rockiroads
ID: 18857111
The fixed approach, not a good idea if u know the values will differ eg
192.168.100.1 will produce the same result as 192.168.10.1
here is the fixed approach

select Left$(myIpField, 3), Mid$(myIpField, 5, 3), Mid$(myIpField, 9, 2)
from mytable
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Author Comment

by:westermo
ID: 18857174
Simply brilliant.  Thank you Rockiroads
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LVL 65

Expert Comment

by:rockiroads
ID: 18857205
No probs, glad to have helped
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