Get substring.

Given

'3 - La Senza DEV' in variable div.Name.

I just want La Senza DEV. The following does not work.

 selectedDivName = Right(div.Name, 4)
                   
mathieu_cuprykAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

YZlatCommented:

 selectedDivName = Left(div.Name, div.Name.Length - 4)
0
YZlatCommented:
use this because .NET does not have Left function
selectedDivName = div.Name.Substring(4,div.Name.Length - 1)
0
SStoryCommented:
Not sure what language or how you want to determine what you are after.
Your code says, "give me the 4 right most chars which would be " DEV"

If this is Dot Net

then div.name.substring(4) would give you all the chars besides the first 4.

You need to provide more info as to how you are going to determine how many chars from which side you want to get.
0
Cloud Class® Course: Microsoft Exchange Server

The MCTS: Microsoft Exchange Server 2010 certification validates your skills in supporting the maintenance and administration of the Exchange servers in an enterprise environment. Learn everything you need to know with this course.

mathieu_cuprykAuthor Commented:
DOes not work lol
0
Jeff CertainCommented:
The LEFT and RIGHT functions require the import of the Microsoft.VisualBasic compatibility library.

You're going to run into issues if you have more than one digit at the beginning.

Try selectedDivName  = div.Name.Substring(div.IndexOf("-"c) + 1)
0
YZlatCommented:
try

selectedDivName = div.Name.ToString.Substring(4,div.Name.Length - 1)
0
YZlatCommented:
or

selectedDivName = div.Name.ToString.Substring(4,div.Name.ToString.Length - 1)
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
r1937Commented:
       '-----Read to end
        Dim MyString As String = "3 - La Senza DEV"
        Dim Start As Integer = 7
        MsgBox(MyString.Substring(Start, MyString.Length - Start))
0
r1937Commented:
       '-----Read to end
        Dim MyString As String = "3 - La Senza DEV"
        Dim Start As Integer = 4
        MsgBox(MyString.Substring(Start, MyString.Length - Start))

        '-----Or if you want old visual basic stuff-----

        MsgBox(Microsoft.VisualBasic.Right(MyString, 12))
0
SStoryCommented:
If you want tot use the old VB library do an

imports microsoft.visualbasic at the top of the code.

There's nothing wrong with this. C programmer use their libraries and would be lost without them.
While it's true that you can use substring to accomplish a LEFT or RIGHT, it would be a lot simpler if Microsoft had included a left and right on the String class (even if it just called the substring function internally.  At the least a Right function would have been nice.

The bottom line is that if you have a string

dim s as string="WHATEVER"

if you want the left 4 chars
s.substring(0,4) should give it to you the same as Left(s,4)

If you want the right side minus 4 chars

s.substring(4,s.length-4) will give you this

4 could obviouly be some variable if you like.

s.substring(4) in this example start at the 5th char and gives you all the rest
which would be "EVER"

Given a string, this is how you do Left, and Right
Mid could be accomplished such as
s.substring(4,2) which would return "EV" in this case

Your question seems more than answered by multiple people.

If it isn't then you need to be a lot more specific.  

0
SanclerCommented:
From ".NET Framework Class Library - Strings.Mid Method (String, Int32, Int32)"

>>
Parameters
str
Required. String expression from which characters are returned.

Start
Required. Integer expression. Starting position of the characters to return. If Start is greater than the number of characters in str, the Mid function returns a zero-length string (""). Start is one based.

Length
Optional. Integer expression. Number of characters to return. If omitted or if there are fewer than Length characters in the text (including the character at position Start), all characters from the start position to the end of the string are returned.

[...]

This example uses the Mid function to return a specified number of characters from a string.

Visual Basic
' Creates text string.
Dim TestString As String = "Mid Function Demo"
' Returns "Mid".
Dim FirstWord As String = Mid(TestString, 1, 3)
' Returns "Demo".
Dim LastWord As String = Mid(TestString, 14, 4)
' Returns "Function Demo".
Dim MidWords As String = Mid(TestString, 5)

<<

So, with the data you give, you want - in .NET (not heritage Visual Basic) code - and assuming both selectedDivName and div.Name are declared as Strings

    selectedDivName = Mid(div.Name, 5)

Roger
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Visual Basic.NET

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.