How to remove values and parentheses from a string?


How can I only return the string value that is not included within parentheses?  For example, if I have an element <LINK TTL="17" S="210.4-01(a)(3)(i)(A)"> and I would only like the @S attribute to only return "210.4-01", how can this be processed?

Any advice or guidance is greatly appreciated!

Best regards,
Who is Participating?
BobSiemensConnect With a Mentor Commented:

This is a quick, typed from the top of my head, method.  

Basically, you recursively call the function.  It will dump the whole string if there are no parens.  If there are parens, it dumpt the pre-paren part and calls itself with the post-paren part.

<xsl:template name="DumpNonParenData">
  <xsl:param name="TheString" />
    <xsl:when test="contains($TheString, '(')">
      <xsl:value-of select="substring-before($TheString, '(')"/>
      <xsl:call-template name="DumpNonParenData">
        <xsl:with-param name="TheString" >
          <xsl:value-of select="substring-after($TheString, ')')"/>
      <xsl:value-of select="$TheString"/>
<xsl:template name="DumpNonParenData">
  <xsl:param name="TheString" />
    <xsl:when test="contains($TheString, '(')">

Geert BormansConnect With a Mentor Information ArchitectCommented:
If you are using XSLT1 you need a recursive method as Bob suggested

This example is a perfect usecase for XSLT2 though.
(If I had to do some similar things like this in a project, I would use XSLT2)
So if by any chance you can use Saxon8B in this project,
I recommend you do
Here is the XSLT2 solution, look how easy with regular expressions

    <xsl:template match="LINK">
        <xsl:value-of select="replace(@S, '\([^\)]+\)', '')" />


jmc430Author Commented:
Hi Geert,

Thanks for your helpful response!
I cannot use Saxon8B, but I appreciate your comments!

Hi BobSiemens,

Thanks for your solution.  It works!

Thanks again and happy holidays! :)
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