SQL Aggregation Question

If I had a table with some data ordered by date.  Is there a way I can pull the data to aggregate the data based on the individual day?  So if I had a table with one column is Date, the other is Amount.  I want to return a selection that  has a row for each distinct date and the sum of all the amounts on that date.  Thanks
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kayhustleAsked:
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Cornelia YoderArtistCommented:
SELECT Date, SUM(Amount) FROM Table GROUP BY Date
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kayhustleAuthor Commented:
Ok, lets say the actual date field could be 11:30pm 1/1/07 or 12:30 1/1/07, but I want it to aggregate by day, even though the dates in the table are aggregated by hour?
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Cornelia YoderArtistCommented:
Assuming you are using a datetime field, you can GROUP BY SUBSTRING(Date FROM 0 FOR 10)

This picks off the first 10 characters of the Date field, which should be 2007-04-10 format.
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Cornelia YoderArtistCommented:
There are also MySQL functions YEAR, MONTH, DAY, so you might try

GROUP BY YEAR(Date), MONTH(Date), DAY(Date).  

I'm not sure which would be more efficient, so if it matters, you might want to try both and put a timer on to see which way is faster.
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Guy Hengel [angelIII / a3]Billing EngineerCommented:
as you posted in SQL Server 2005, I suggest to give you the mssql query:

select CONVERT(varchar(10), yourdatefield, 120) as day_value , sum(amount) sum_amount
FROM yourtable
group by CONVERT(varchar(10), yourdatefield, 120)
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Microsoft SQL Server 2005

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