collision detection in c#

in panel1; an arrayList or some object to keep track of the image and it's position. if the user drop an
image on top of another image, the is a messegeBox that shows."there is a preexisting image in the
desire location, do you wich to delete the preexisting image; Yes or No". if yes, the old image is deleted
and the new image is place at that location. if No, the old image remains. you can't put a pictureBox on
the top of another in the drop area.

this the program;  you insert pictureBoxs in panel2 and load them with image. you can drag and drop the
image in panel1

bool pbDown = false;
        PictureBox selectedPB;
        Rectangle prevClip;
        PictureBox pb;
        int startX, startY;
        ContextMenu cm = new ContextMenu();

private void DesignForm_Load(object sender, EventArgs e)
        {
            this.Reset();
            prevClip = Cursor.Clip;
            foreach (Control ctl in panel2.Controls)
            {
                if (ctl is PictureBox)
                {
                    ctl.MouseDown += new MouseEventHandler(ctl_MouseDown);
                    ctl.MouseMove += new MouseEventHandler(ctl_MouseMove);
                    ctl.MouseUp += new MouseEventHandler(ctl_MouseUp);
                }
            }
            MenuItem delete = new MenuItem("Delete");
            delete.Click += new EventHandler(delete_Click);
            cm.MenuItems.Add(delete);
            panel1.Click += new EventHandler(panel1_Click);
            panel1.MouseMove += new MouseEventHandler(panel1_MouseMove);

        }

        private void panel1_Click(object sender, EventArgs e)
        {
            if (selectedPB != null)
            {
                selectedPB.BorderStyle = BorderStyle.None;
                selectedPB = null;
            }

        }

        private void panel1_MouseMove(object sender, MouseEventArgs e)
        {
            if (selectedPB != null && pbDown)
            {
                System.Diagnostics.Debug.Print("Too Fast!...panel1_MouseMove(" + e.X.ToString() + ", " + e.Y.ToString() + ")");
                Point pt = panel1.PointToScreen(new Point(e.X, e.Y));
                pt = selectedPB.PointToClient(pt);
                MouseEventArgs mea = new MouseEventArgs(MouseButtons.Left, 0, pt.X, pt.Y, 0);
                pb_MouseMove(selectedPB, mea);
            }
        }
       

        void delete_Click(object sender, EventArgs e)
        {
            MenuItem mi = (MenuItem)sender;
            ContextMenu cm = (ContextMenu)mi.GetContextMenu();
            PictureBox pb = (PictureBox)cm.SourceControl;
            pb.Dispose();
        }

        void ctl_MouseDown(object sender, MouseEventArgs e)
        {
            if (e.Button == MouseButtons.Left)
            {
                Cursor.Clip = this.RectangleToScreen(this.ClientRectangle);
                startX = e.X;
                startY = e.Y;
                PictureBox source = (PictureBox)sender;
                pb = new PictureBox();
                pb.Size = source.Size;
                pb.Location = this.PointToClient(panel2.PointToScreen(source.Location));
                pb.Image = source.Image;
                this.Controls.Add(pb);
                pb.BringToFront();
            }
        }

        void ctl_MouseMove(object sender, MouseEventArgs e)
        {
            if (e.Button == MouseButtons.Left)
            {
                if (pb != null)
                {
                    pb.Location = new Point(pb.Location.X + (e.X - startX), pb.Location.Y + (e.Y - startY));
                    startX = e.X;
                    startY = e.Y;
                }
            }
        }

        void ctl_MouseUp(object sender, MouseEventArgs e)
        {
            if (e.Button == MouseButtons.Left)
            {
                if (pb != null)
                {
                    Cursor.Clip = prevClip;
                    if (pb.ClientRectangle.IntersectsWith(panel1.ClientRectangle))
                    {
                        pb.Hide();
                        pb.Location = panel1.PointToClient(this.PointToScreen(pb.Location));
                        panel1.Controls.Add(pb);
                        pb.ContextMenu = cm;
                        pb.Show();

                        pb.MouseDown += new MouseEventHandler(pb_MouseDown);
                        pb.MouseMove += new MouseEventHandler(pb_MouseMove);
                        pb.MouseUp += new MouseEventHandler(pb_MouseUp);
                    }
                    else
                    {
                        pb.Dispose();
                    }
                    pb = null;
                }
            }
        }

        void pb_MouseDown(object sender, MouseEventArgs e)
        {
            if (e.Button == MouseButtons.Left)
            {
                pbDown = true;
                if (selectedPB != null)
                {
                    selectedPB.BorderStyle = BorderStyle.None;
                    selectedPB = null;
                }
                selectedPB = (PictureBox)sender;
                selectedPB.BorderStyle = BorderStyle.FixedSingle;
                selectedPB.BringToFront();
                Rectangle pnl = this.RectangleToScreen(new Rectangle(panel1.Location, panel1.Size));
                pnl.X = pnl.X + 1;
                pnl.Width = pnl.Width - 2;
                pnl.Y = pnl.Y + 1;
                pnl.Height = pnl.Height - 2;
                Cursor.Clip = pnl;
                startX = e.X;
                startY = e.Y;
            }
        }

        void pb_MouseMove(object sender, MouseEventArgs e)
        {
            if (e.Button == MouseButtons.Left)
            {
                PictureBox localPB = (PictureBox)sender;
                if (localPB == selectedPB)
                {
                    localPB.Location = new Point(localPB.Location.X + (e.X - startX), localPB.Location.Y + (e.Y - startY));
                }
            }
        }

        void pb_MouseUp(object sender, MouseEventArgs e)
        {
            pbDown = false;
            Cursor.Clip = prevClip;
        }

       
       
    }
}
LVL 1
sayethAsked:
Who is Participating?

[Product update] Infrastructure Analysis Tool is now available with Business Accounts.Learn More

x
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

Bob LearnedCommented:
Where is the question?  What are you having a problem with--the MouseUp event code?

Bob
0
Jens FiedererTest Developer/ValidatorCommented:
Very nice presentation of a scenario, but you forgot to form a QUESTION.
0
sayethAuthor Commented:
this program only drag and drop, i want it to also do collision detection.

I want the program to  also do this ( in panel1; an arrayList or some object to keep track of the image and it's position. if the user drop an image on top of another image, the is a messegeBox that shows."there is a preexisting image in the desire location, do you wich to delete the preexisting image; Yes or No". if yes, the old image is deleted and the new image is place at that location. if No, the old image remains. you can't put a pictureBox on the top of another in the drop area)
0
Bootstrap 4: Exploring New Features

Learn how to use and navigate the new features included in Bootstrap 4, the most popular HTML, CSS, and JavaScript framework for developing responsive, mobile-first websites.

Bob LearnedCommented:
You have the tools, you just need to put them together:

pb.ClientRectangle.IntersectsWith(panel1.ClientRectangle)

Loop through the controls for the panel, and determine if any of the controls are PictureBox, and the if the PictureBox control intersects with the rectangle referenced by 'pb'.

Bob
0
sayethAuthor Commented:
can you please show me in the code, because i been messing with this thing all night and i can't get it to work right
0
Bob LearnedCommented:
Untested attempt:

private bool PictureBoxHitTest(PictureBox pb1)
{
  foreach (Control ctl in panel2.Controls)
  {
     if (typeof(ctl) == typeof(PictureBox))
     {
        pb2 = (PictureBox)ctl;
        if (pb.ClientRectangle.IntersectsWith(pb2.ClientRectangle))
          return true;
     }
  }
  return false;
}

Bob
0
sayethAuthor Commented:
there is one error on the commented line;
Error: The type or namespace name 'ctl' could not be found (are you missing a using directive or an assembly reference?)      
private bool PictureBoxHitTest(PictureBox pb1)
{
  foreach (Control ctl in panel2.Controls)
  {
    // if (typeof(ctl) == typeof(PictureBox))
     {
        pb2 = (PictureBox)ctl;
        if (pb.ClientRectangle.IntersectsWith(pb2.ClientRectangle))
          return true;
     }
  }
  return false;
}
0
Bob LearnedCommented:
Try this:

private bool PictureBoxHitTest(PictureBox pb1)
{
  foreach (Control ctl in panel2.Controls)
  {
    if (ctl.GetType() == typeof(PictureBox))
     {
        pb2 = (PictureBox)ctl;
        if (pb.ClientRectangle.IntersectsWith(pb2.ClientRectangle))
          return true;
     }
  }
  return false;
}

Bob
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
sayethAuthor Commented:
i am sorry, i had a family problem i needed to take care of. but i am back. your code look perfect, sweet and it is right ; however, when i call it in the program above it don't do nothing.
0
sayethAuthor Commented:
ok, it do something, it don't allow any drop.
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
C#

From novice to tech pro — start learning today.