Not correct IP sorting in DBGRID

yup, but you have to sort them as integers

ip = a.b.c.d

int_ip = a*256^3 + b*256^2 + c*256^1 + d*256^0

ziolko.

Another way is formating IP number as string of XXX.XXX.XXX.XXX... that is... each block has to have 3 digits... completed with leading zeros if you must.

speaker.

How to do this with SQL ???
select * from table order by IP

IP field is an string field?
With which database are you working with

Looking for a solution under LocalSQL with BDE...

But, perhaps the best solution is to store the fields as a string just formated as i stated above (xxx.xxx.xxx.xxx). Then if you want to show ip numbers like 192.168.1.1 instead of 192.168.001.001 you can include a calculated field and reformat the string to its original value with Delphi function.

yes IP is a string field
i use microsoft SQL server
and IP adresses stored as 192.168.1.15

I do not know if you can in MS-SQL, but you may parse each part of IP string as an integer, then order as

select parsepart1asinteger as part1,
parsepart2asinteger as part2,
parsepart3asinteger as part3,
parsepart4asinteger as part4,
ip
from ipnumbers
order part1, part2, part3, part4

where parsepartNasinteger is a sql function like:

cast( substring(ip from N1 for N2) as integer)

where N1 and N2 has to be the value of the location of the separator point (except for N1 in first string and N2 in last string).

I really do not know if there is a MS-SQL function that do this work. Perhaps you have to ask this question in MS-SQL Server zone.

Hope this help!!!

MsSQL sintax... probably :-)... can test it

select cast(substring(ip from 1 for charindex('.',ip)-1) as integer) as part1,
          cast(substring(ip from charindex('.',ip)+1 for charindex('.',ip, charindex('.',ip)+1) as integer) as part2,
          cast(substring(ip from charindex('.',ip, charindex('.',ip)+1)+1 for charindex('.',ip, charindex('.',ip, charindex('.',ip)+1)+1) as integer) as part3,
          cast(substring(ip from charindex('.',ip, charindex('.',ip, charindex('.',ip)+1)+1) +1 for charindex('.',ip, charindex('.',ip, charindex('.',ip,charindex('.',ip)+1)+1)+1) as integer) as part4, ip

from ipnumbers

order by part1, part2, part3, part4

This might work... Found examples of this in:

http://www.sqlbooks.ru/readarticle.aspx?part=09&file=addition09
or
http://www.databasejournal.com/features/mssql/article.php/3071531

Must work!