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How do I format the output a mktime variable?

Posted on 2007-07-22
Medium Priority
Last Modified: 2008-03-06

I am using the following script to display a calendar.  The calendar uses mktime, a namespace that I have little experience with.  The date is stored in a variable called $date.  I would like to output the selected date in a format, ie. 01-12-2007.  Here is the script;

ini_set('display_errors', '0');
// Gather variables from
// user input and break them
// down for usage in our script

   $date = mktime(0,0,0,date('m'), date('d'), date('Y'));
} else {
   $date = $_REQUEST['date'];

$day = date('d', $date);
$month = date('m', $date);
$year = date('Y', $date);

// Get the first day of the month
$month_start = mktime(0,0,0,$month, 1, $year);

// Get friendly month name
$month_name = date('M', $month_start);

// Figure out which day of the week
// the month starts on.
$month_start_day = date('D', $month_start);

    case "Sun": $offset = 0; break;
    case "Mon": $offset = 1; break;
    case "Tue": $offset = 2; break;
    case "Wed": $offset = 3; break;
    case "Thu": $offset = 4; break;
    case "Fri": $offset = 5; break;
    case "Sat": $offset = 6; break;

// determine how many days are in the last month.
if($month == 1){
   $num_days_last = cal_days_in_month(0, 12, ($year -1));
} else {
   $num_days_last = cal_days_in_month(0, ($month -1), $year);
// determine how many days are in the current month.
$num_days_current = cal_days_in_month(0, $month, $year);

// Build an array for the current days
// in the month
for($i = 1; $i <= $num_days_current; $i++){
    $num_days_array[] = $i;

// Build an array for the number of days
// in last month
for($i = 1; $i <= $num_days_last; $i++){
    $num_days_last_array[] = $i;

// If the $offset from the starting day of the
// week happens to be Sunday, $offset would be 0,
// so don't need an offset correction.

if($offset > 0){
    $offset_correction = array_slice($num_days_last_array, -$offset, $offset);
    $new_count = array_merge($offset_correction, $num_days_array);
    $offset_count = count($offset_correction);

// The else statement is to prevent building the $offset array.
else {
    $offset_count = 0;
    $new_count = $num_days_array;

// count how many days we have with the two
// previous arrays merged together
$current_num = count($new_count);

// Since we will have 5 HTML table rows (TR)
// with 7 table data entries (TD)
// we need to fill in 35 TDs
// so, we will have to figure out
// how many days to appened to the end
// of the final array to make it 35 days.

if($current_num > 35){
   $num_weeks = 6;
   $outset = (42 - $current_num);
} elseif($current_num < 35){
   $num_weeks = 5;
   $outset = (35 - $current_num);
if($current_num == 35){
   $num_weeks = 5;
   $outset = 0;
// Outset Correction
for($i = 1; $i <= $outset; $i++){
   $new_count[] = $i;

// Now let's "chunk" the $all_days array
// into weeks. Each week has 7 days
// so we will array_chunk it into 7 days.
$weeks = array_chunk($new_count, 7);

// Build Previous and Next Links
$previous_link = "<a href=\"".$_SERVER['PHP_SELF']."?messageid=$messageid&date=";
if($month == 1){
   $previous_link .= mktime(0,0,0,12,$day,($year -1));
} else {
   $previous_link .= mktime(0,0,0,($month -1),$day,$year);
$previous_link .= "\"><< Prev</a>";

$next_link = "<a href=\"".$_SERVER['PHP_SELF']."?messageid=$messageid&date=";
if($month == 12){
   $next_link .= mktime(0,0,0,1,$day,($year + 1));
} else {
   $next_link .= mktime(0,0,0,($month +1),$day,$year);
$next_link .= "\">Next >></a>";

// Build the heading portion of the calendar table
echo "<table border=\"1\" cellpadding=\"2\" cellspacing=\"0\" width=\"300\" class=\"calendar\">\n".
     "<td colspan=\"7\">\n".
     "<table align=\"center\">\n".
     "<td colspan=\"2\" width=\"75\" align=\"left\">$previous_link</td>\n".
     "<td colspan=\"3\" width=\"150\" align=\"center\">$month_name $year</td>\n".
     "<td colspan=\"2\" width=\"75\" align=\"right\">$next_link</td>\n".

// Now we break each key of the array  
// into a week and create a new table row for each
// week with the days of that week in the table data

$i = 0;
foreach($weeks AS $week){
       echo "<tr>\n";
       foreach($week as $d){
         if($i < $offset_count){
             $day_link = "<a href=\"".$_SERVER['PHP_SELF']."?messageid=$messageid&date=".mktime(0,0,0,$month -1,$d,$year)."\">$d</a>";
             echo "<td class=\"nonmonthdays\">$day_link</td>\n";
         if(($i >= $offset_count) && ($i < ($num_weeks * 7) - $outset)){
            $day_link = "<a href=\"".$_SERVER['PHP_SELF']."?messageid=$messageid&date=".mktime(0,0,0,$month,$d,$year)."\">$d</a>";
           if($date == mktime(0,0,0,$month,$d,$year)){
               echo "<td class=\"today\">$d</td>\n";
           } else {
               echo "<td class=\"days\">$day_link</td>\n";
        } elseif(($outset > 0)) {
            if(($i >= ($num_weeks * 7) - $outset)){
               $day_link = "<a href=\"".$_SERVER['PHP_SELF']."?messageid=$messageid&date=".mktime(0,0,0,$month +1,$d,$year)."\">$d</a>";
               echo "<td class=\"nonmonthdays\">$day_link</td>\n";
      echo "</tr>\n";    

// Close out your table and that's it!
echo '<tr><td colspan="7" class="days"> </td></tr>';
echo '</table>';
Question by:mhouldridge
1 Comment

Accepted Solution

punkstar earned 2000 total points
ID: 19542933
Assuming you are British, to output a unix timestamp held in the $date variable from a mktime() call, you can get the desired day-month-year output with:

echo date("d-m-Y", $date);

If on the other hand you are American and you want the month to come before the date, you can use the call:

echo date("m-d-Y", $date);

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