IP address as string - determine if it is longer or short then the other - vb.net

Hello nahumba,

string1.Length > string2.Length

Regards,
Martin

Hi martin,
This will not always work (I think), since the actual length does not always represents the IP address lentgh...

what do you mean ?
can you give some examples so I can be more strict in suggestions ?

Martin

My application needs to scan a range of IPs from a given start address to an end address.

I need to determine that the start address's length is shorter.. What I actually mean is, that the IP address length is determined by it's byte size (each octet is between 0 to 255) 32bits in total...

So the string's length value just return the number of total characters in the string, I need to determine the IP address's byte size..

You can do something like this

   'Assumption IP is in valid IPV4 format
    Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
        Dim ip1 As String = "255.255.255.255"
        Dim ip2 As String = "2.2.2.2"
        Dim lngip1 As Long = getIPAsLong(ip1)
        Dim lngip2 As Long = getIPAsLong(ip2)

        If lngip1 > lngip2 Then
            MessageBox.Show("ip1 is larger then ip2")
        ElseIf lngip1 = lngip2 Then
            MessageBox.Show("ip1 is equal to  ip2")
        Else 'lngip1 < lngip2
            MessageBox.Show("ip1 is smaller than  ip2")
        End If
    End Sub

    Private Function getIPAsLong(ByVal str As String) As Long
        Dim sRes As String
        Dim i As Integer
        Dim aStr() As String
        aStr = str.Split(".")
        For i = 0 To aStr.Length - 1
            sRes &= paddingZero(aStr(i))
        Next
        Return CLng(sRes)

    End Function

    Private Function paddingZero(ByVal str As String) As String
        Dim res As String = str.Trim
        If (res.Length >= 3) Then
            res = res.Substring(0, 3)
        Else
            While (res.Length < 3)
                res = "0" & res

            End While
        End If
        Return res
    End Function

Thank you Martin - exactly what I've been looking for!