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ListBox, how to get the item pick and do something with it

Posted on 2007-08-07
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Last Modified: 2013-11-05
hi,
How can i show in a message box the item selected on a listBox?

here is the code i'm using:

 Private Sub frmTableMaintenance_Shown(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Shown

        Dim dt As DataTable = com.library.data.Tools.GetTableAccess()
        Dim dtrw As DataRow
        dtrw = dt.Rows(0)

        For Each dtrw In dt.Rows
            strFormName.Items.Add(dtrw("strTableName"))
        Next

        MsgBox("You have Selected: " & strFormName.SelectedItem)

    End Sub
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Question by:jsctechy
  • 2
3 Comments
 
LVL 38

Accepted Solution

by:
PaulHews earned 1000 total points
ID: 19649799
You've just added items to the listbox, so there shouldn't be any selecteditem property at this point.  The thing to do would be trap the SelectedIndexChangedevent:

Private Sub strFormName_SelectedIndexChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles strFormName.SelectedIndexChanged
    If strFormName.SelectedIndex > -1 Then
        MsgBox("You've selected " & strFormName.SelectedItem.ToString)
    End If
End Sub
0
 
LVL 1

Author Comment

by:jsctechy
ID: 19649859
if i need to open a form with the name that gets passed on the msgBox how can i do this?

for nstance lets said my first value is frmTax then once i double click on it the message box will display but instead of doing this i want to display the form that has the same name?
0
 
LVL 38

Expert Comment

by:PaulHews
ID: 19653065
If you really need to do that you can do it this way:

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
    Dim frm As Form = CType(System.Reflection.Assembly.GetExecutingAssembly.CreateInstance("WindowsApplication1.Form2"), Form)
    frm.ShowDialog()
End Sub

Because it is declared as Form and not as Form2, you will not be able to access any custom properties or methods of Form2.

With a little more code, you can have strongly typed forms:
Select Case FormName
    Case "Form2"
        Dim frm As Form2
        If frm.ShowDialog = Windows.Forms.DialogResult.OK Then
            'use custom methods of Form2...
        End If
    Case "Form3"
        '...
End Select
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