Reading some file names on the server and creating a variable

Posted on 2007-09-27
Medium Priority
Last Modified: 2010-05-19
I have some files in the "./files/" directory.
Some of these files are named "random_001.jpg", "random_002.jpg", "random_003.jpg" etc...

I need PHP to look in this directory and find all of the "random_XXX.jpg" files and find the last one (the highest numbered file).
I need that number as a variable.

On top of that...
If the number is "005", for instance, I only want the variable to be "5"
If the number is "020", I want the variable to be "20" and so on.

Can someone throw that little script together?

Question by:innercproductions
1 Comment
LVL 35

Accepted Solution

Terry Woods earned 2000 total points
ID: 19975668
  $dir = "./files/";
    if ($dh = opendir($dir)) {
      while ( ($file = readdir($dh)) !== false) {
        echo "Looking at $dir/$file<br>\n";
        if (is_file("$dir/$file")
            && is_readable("$dir/$file")
            && preg_match('@random_\d\d\d\.jpg$@i',$file)
           ) {
          $fileNum = preg_replace('@random_0*(\d{0,3})\.jpg@','$1',$file);
          echo "File number is $fileNum<br>\n";
          if (!isset($maxNum) || $fileNum > $maxNum) {
            $maxNum = $fileNum;
            echo "Max number is now $maxNum<br>\n";
            echo "File with this number is $dir$file<br>\n";



Looking at ./files//.
Looking at ./files//..
Looking at ./files//random_123.jpg
File number is 123
Max number is now 123
File with this number is ./files/random_123.jpg
Looking at ./files//random_034.jpg
File number is 34
Looking at ./files//random_245.jpg
File number is 245
Max number is now 245
File with this number is ./files/random_245.jpg

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