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# 3 Character  Permutation Algorithm

searchei asked
on
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Last Modified: 2008-05-05
I am trying to figure out how to do what I think is a permutation.  I need to develop an algorithm to calculate all the different possibilities of a 3 character in length string with containing the characters 0-9 and A-Z in each of the 3 positions.  For instance like the following.  (I hope you get the gist of what I need)

A00  A10   A11            B00  0A0
A01  A20   A12            B01  0B0
A02...A30.. A13.........  B02   0C0

But all the different sequences of 36 characters 0-9 A-Z

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Commented:
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Senior Software Developer
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Top Expert 2009

Commented:
Oops there was a typo (36 ^ 3) = 46656
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Commented:
It sounds like you want to count to 36 in 3 nested loops
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Commented:
OK, Thanks.  Here's a bonus for you if you want to do this with a string:

int main(int argc, char *argv[])
{
int i,j,k;

char list[]="ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
char string_result[4];

string_result[3]=0;         /* NUL terminate the string */

for (i=0; i<36; i++)
{
string_result[0]=list[i];               /* Set x__ */
for (j=0; j<36; j++)
{
string_result[1]=list[j];           /* Set _y_ */
for (k=0; k<36; k++)
{
string_result[2]=list[k];       /* Set __z */
printf("%s\n",string_result);   /* Print xyz */
}
}
}
return 0;
}

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