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enable "option explicit" c#

Posted on 2007-10-07
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Last Modified: 2010-05-18
Hi there,

I have a new computer and started coding a new project, C#.

I noticed i did not apply ToString() to a int variable when combining it with string.

E.g.
int maxLength = 50;
throw new Exception.EntityException_FieldLength("Last Name is limited to " + maxLength + " characters");

This compiles! How do i fix it so the compiler tells me to fix the code? For the life of me i cannot see the option in the editor.

I would expect to have to write
throw new Exception.EntityException_FieldLength("Last Name is limited to " + maxLength-->.ToString()<-- + " characters");

thanks!
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Question by:Valimai
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anarki_jimbel earned 1000 total points
ID: 20032308
It is not Visual Basic, it's C# and it is a bit different.

Basicly, "+" operator is overloaded so that if you are trying to concatenate a string and a number - it's OK.

Explanation from http://www.thescripts.com/forum/thread577964.html:
"
mmm... I took a look to the IL produced.
C# compiler to concatenate strings call string.Concat().
Since there is not string.Concat(string, int) the called overload is
string.Concat(object, object).
If you look inside it (I used Reflector) you can see

return (arg0.ToString() + arg1.ToString());

So this is the discovered secret :)
"
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Assisted Solution

by:anarki_jimbel
anarki_jimbel earned 1000 total points
ID: 20032364
I didn't answer how can you switch on http://msdn2.microsoft.com/en-us/library/aa288467(VS.71).aspxtion explicit". There is no such an option. However if you really need on some a reason you may consider overriding the "+" operator like in:
http://msdn2.microsoft.com/en-us/library/aa288467(VS.71).aspx

( Honestly, not sure if it is possible in case of strings and numbers).

By the way, other languages like Java also permit that behaviour.
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Author Comment

by:Valimai
ID: 20032418
THanks for the articles and it does appear that the code works as designed.

I just can't believe that I could always do this with c#:
int myNumber = 5;
Response.Write("The number is " + myNumber);

No need to respond to this one. I will keep the question open for another day to see if anyone else has a view. Otherwise i will accept your answer.
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