how to evaluate the integral of six*tanx dx

i am working on a differential equation and i need to solve the
integral of (sinx tanx dx )

do i do it by parts ?
c_hocklandAsked:
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bungHocCommented:

sin(x) tan(x) dx = 1/cos(x) dx - cos(x)dx
=Log( cos(x/2) + sin(x/2) ) - Log( cos(x/2) - sin(x/2) ) - sin(x)
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ozoCommented:
that's one way
also, sin(x) tan(x) = (1/cos(x) - cos(x) )
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ozoCommented:
Log( abs(cos(x/2) + sin(x/2)) ) - Log( abs(cos(x/2) - sin(x/2)) )  =  log(abs((1+sin(x))/cos(x)))
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bungHocCommented:
Glad it helped. Thanks for the points.
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