how to evaluate the integral of six*tanx dx

Posted on 2007-10-11
Last Modified: 2010-08-05
i am working on a differential equation and i need to solve the
integral of (sinx tanx dx )

do i do it by parts ?
Question by:c_hockland
    LVL 84

    Expert Comment

    that's one way
    also, sin(x) tan(x) = (1/cos(x) - cos(x) )
    LVL 7

    Accepted Solution


    sin(x) tan(x) dx = 1/cos(x) dx - cos(x)dx
    =Log( cos(x/2) + sin(x/2) ) - Log( cos(x/2) - sin(x/2) ) - sin(x)
    LVL 84

    Assisted Solution

    Log( abs(cos(x/2) + sin(x/2)) ) - Log( abs(cos(x/2) - sin(x/2)) )  =  log(abs((1+sin(x))/cos(x)))
    LVL 7

    Expert Comment

    Glad it helped. Thanks for the points.

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