Concatenate values of a column

Posted on 2007-10-11
Medium Priority
Last Modified: 2013-12-19
I have a table Company with columns like Phone_Num, Fax and email where they can have multiple values.
These values should be return in a single row.
The table below shed more light on the scenario
Company | Phone_Num | Fax | email
AG             0345             45       ab@rt.com
AG             0378             47      ab@rt.com
GB             0256            34       gb@rt.com
GB            0298             34       gb2@rt.com
RD            0449              67       rd@rt.com

I would the result of my query be

Company | Phone_Num | Fax   | email
AG              0345,0378   45,47   ab@rt.com
GB               0256,0256   34       gb@rt.com,gb2@rt.com
RD                    0449        67       rd@rt.com

I am thinking of creating a function given the name of the company, it returns a
string in the pattern the "Phone_NUm#Fax&email". Using string functions like substring and length
I would split it in the respective variables.
My problem is how can I create the oracle function.
Any help would be welcome.
Question by:diteps06
  • 4

Assisted Solution

fmonroy earned 60 total points
ID: 20059061
You can get syntaxis here:

nad yes, your idea is correct, receive the company ID as an argument to your function and cicle thru all the values (maybe using cursor) concatenating the results. Finally return the string.
LVL 74

Assisted Solution

sdstuber earned 315 total points
ID: 20061842
go to asktom.oracle.com  and search for STRAGG,  

then your query simply becomes....

SELECT   company,
         stragg(DISTINCT phone_num) phone_num,
         stragg(DISTINCT fax) fax,  
         stragg(DISTINCT email) email
    FROM your_table
GROUP BY company
LVL 74

Assisted Solution

sdstuber earned 315 total points
ID: 20061980
or, if you want to do it purely in sql and avoid pl/sql and new functions then you can try this....


Note in all cases your concatenated string must not grow longer than 4000 characters or you'll
get a sql error

SELECT company, RTRIM(phone_num_path, ',') phone_num, RTRIM(fax_path,
                                                            ',') fax,
       RTRIM(email_path, ',') email
  FROM (SELECT     company, phone_num, prev_phone, fax, prev_fax, email,
                                                WHEN phone_num = prev_phone
                                                 OR phone_num = next_phone
                                                    THEN NULL
                                                ELSE phone_num
                       ) phone_num_path,
                                                WHEN fax = prev_fax
                                                 OR fax = next_fax
                                                    THEN NULL
                                                ELSE fax
                       ) fax_path,
                                                WHEN email = prev_email
                                                 OR email = next_email
                                                    THEN NULL
                                                ELSE email
                       ) email_path,
                   CONNECT_BY_ISLEAF isleaf, LEVEL l
              FROM (SELECT company, phone_num, fax, email,
                           LAG(phone_num, 1) OVER(PARTITION BY company ORDER BY phone_num)
                           LAG(fax, 1) OVER(PARTITION BY company ORDER BY fax)
                           LAG(email, 1) OVER(PARTITION BY company ORDER BY email)
                           LEAD(phone_num, 1) OVER(PARTITION BY company ORDER BY phone_num)
                           LEAD(fax, 1) OVER(PARTITION BY company ORDER BY fax)
                           LEAD(email, 1) OVER(PARTITION BY company ORDER BY email)
                           ROW_NUMBER() OVER(PARTITION BY company ORDER BY phone_num)
                      FROM people)
        CONNECT BY company = PRIOR company AND rn > PRIOR rn
        START WITH rn = 1)
 WHERE isleaf = 1
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LVL 74

Assisted Solution

sdstuber earned 315 total points
ID: 20081753
Any of these options help?  Need an explanation for any of them?

Author Comment

ID: 20084194
I would like to have a solution the to the proposal I made. Your solution is good but complex.
Is there a method to use the STRAGG  function without the group by clause.
LVL 74

Accepted Solution

sdstuber earned 315 total points
ID: 20084838
You are aggregating your data, so you must use a GROUP BY or an analytic...
If you're concerned with the complexity of STRAGG, don't be.
A user defined aggregate is what you're trying to write, so you would just be reinventing that function

Plus, Tom Kyte's site provides all the code and is ready to run "as is" so there's really no downside to it.

To use stragg as an analytic instead of an aggregate, it would look something like this...

         stragg(DISTINCT phone_num)  over (partition by company) phone_num,
         stragg(DISTINCT fax) over (partition by company) fax,  
         stragg(DISTINCT email) over (partition by company) email
    FROM your_table

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