shilpi84
asked on
problem with 2D char array
Please tell me what's wrong with the initialization of this 2D char array a[10][2];
I've tried with curly brackets too, but nothing happends. With round brackets, ASCII values get stored;
#include<iostream>
#include<conio.h>
#include<string.h>
using namespace std;
class loj
{
char a[10][2];
string s;
char b[2];
int j;
public:
void input();
void logic();
loj();
};
loj::loj()
{
a[10][2]=(
('n','o'),
('p','a'),
('r','e'),
('c','i'),
('v','o'),
('m','u'),
('x','a'),
('z','e'),
('b','i'),
('s','o')
);
//to test the value of a[10][2];
for(int i=0;i<2;i++)
for(int j=0;i<10;j++)
cout<<a[i][j];
j=0;
}
void loj::input()
{
cout<<"enter a lojo string\n";
cin>>s;
cout<<"sd";
}
void loj::logic()
{
cout<<s;
for(int i=0;i<s.length();i++)
{
while(j<=1)
{
b[j]=s[i];
j++;
}
if(j==2){
for(int k=0;k<=9;k++)
{
if((b[0]==a[0][k])&&(b[1]= =a[0][k]))
{
cout<<i<<"\t";
}
}
j=0;
}
}
}
int main()
{
loj l;
l.input();
l.logic();
getche();
}
I've tried with curly brackets too, but nothing happends. With round brackets, ASCII values get stored;
#include<iostream>
#include<conio.h>
#include<string.h>
using namespace std;
class loj
{
char a[10][2];
string s;
char b[2];
int j;
public:
void input();
void logic();
loj();
};
loj::loj()
{
a[10][2]=(
('n','o'),
('p','a'),
('r','e'),
('c','i'),
('v','o'),
('m','u'),
('x','a'),
('z','e'),
('b','i'),
('s','o')
);
//to test the value of a[10][2];
for(int i=0;i<2;i++)
for(int j=0;i<10;j++)
cout<<a[i][j];
j=0;
}
void loj::input()
{
cout<<"enter a lojo string\n";
cin>>s;
cout<<"sd";
}
void loj::logic()
{
cout<<s;
for(int i=0;i<s.length();i++)
{
while(j<=1)
{
b[j]=s[i];
j++;
}
if(j==2){
for(int k=0;k<=9;k++)
{
if((b[0]==a[0][k])&&(b[1]=
{
cout<<i<<"\t";
}
}
j=0;
}
}
}
int main()
{
loj l;
l.input();
l.logic();
getche();
}
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SOLUTION
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ASKER
thanks jkr you cleared my doubts
ASKER
a[10][2]={
{'n','o'},
{'p','a'},
{'r','e'},
{'c','i'},
{'v','o'},
{'m','u'},
{'x','a'},
{'z','e'},
{'b','i'},
{'s','o'}
};