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Compute a ranking based on multiple columns and order the selection by that ranking

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I have a table defined as
Create Table MyTest (ID int Primary Key, MyType varchar(10), Criterion1 int, Criterion2 int)
Insert Into MyTest (ID, MyType, Criterion1, Criterion2) Values (1,'One',42,4)
Insert Into MyTest (ID, MyType, Criterion1, Criterion2) Values (2,'One',43,5)
Insert Into MyTest (ID, MyType, Criterion1, Criterion2) Values (3,'One',44,3)
Insert Into MyTest (ID, MyType, Criterion1, Criterion2) Values (4,'Two',24,7)
Insert Into MyTest (ID, MyType, Criterion1, Criterion2) Values (5,'Two',25,8)
Insert Into MyTest (ID, MyType, Criterion1, Criterion2) Values (6,'Two',26,6)

I'd like to select from this table ordered by a ranking.
For example (1,'One',42,4) would rank 3rd if selected by
Select MyType,Criterion1 from MyTest Order By Criterion1 Desc
and would rank 5th if selected by
Select MyType,Criterion2 from MyTest Order By Criterion2 Desc
I'd like to compute (1,'One',42,4)'s rank as (3+5)/2 and select in order of that rank.

How can I do that?
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Billing Engineer
CERTIFIED EXPERT
Most Valuable Expert 2014
Top Expert 2009

Commented:

select l.*
select id, mytype, criterion1, criterion2
, ( select count(*) from MyTest i where i.mytype = t.mytype and i.criterion1 <= t.criterion1 ) rank1
, ( select count(*) from MyTest i where i.mytype = t.mytype and i.criterion2 <= t.criterion2 ) rank2
from MyTest t
) l
order by (l.rank1 + l.rank2) / 2

note: the /2 is actually not needed :)
Top Expert 2007

Commented:
Thank you for the quick answer!

Running this query, I get
Msg 102, Level 15, State 1, Line 6
Incorrect syntax near ')'.
Billing Engineer
CERTIFIED EXPERT
Most Valuable Expert 2014
Top Expert 2009
Commented:
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Top Expert 2007

Commented:
Beautiful !!  Thank you!

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