XPTY0004: A sequence of more than one item is not allowed as the first argument of string-length()

Hello Expert,

There is one more query with the same xslt...

the code is like...

<xsl:variable name="product" select="./@product|./@class | ./@outputclass"/>
            <xsl:if test="string-length($product)=0 or not($product=concat($hiddenProductName,'only'))">
                  <xsl:value-of disable-output-escaping="yes" select="'&lt;b&gt;'"/>
                  <xsl:call-template name="processTags"/>
                  <xsl:value-of disable-output-escaping="yes" select="'&lt;/b&gt;'"/>
            </xsl:if>

The error is appearing for <xsl:variable name="product" select="./@product|./@class | ./@outputclass"/>
as it contains more than one sequence...

Can you pls suggest the what change will required for the same?

Thanks,
Shailesh

always the same problem,
If you have a selection of nodes, there is no automatic concatenation,
and a string-length requires one single string-type (XPath2 is very tricky about types)
If you want a concatenation, you should use string-join
<xsl:variable name="product" select="string-join((./@product|./@class | ./@outputclass), '')"/>

I don't like the disable-output-encoding here
                  <xsl:value-of disable-output-escaping="yes" select="'&lt;b&gt;'"/>
                  <xsl:call-template name="processTags"/>
                  <xsl:value-of disable-output-escaping="yes" select="'&lt;/b&gt;'"/>

why don't you do this?
                  <b>
                      <xsl:call-template name="processTags"/>
                  </b>


your first example could be done the same way,

cheers

Geert

Hello expert,

Is this applicable for ...<xsl:variable name="firstPassToken" select="substring-before($dest,concat('.',$lastToken))"/>

Thanks,
Shailesh

Hello expert,

<xsl:variable name="firstPassToken" select="substring-before(string-join($dest ,concat('.',$lastToken), ''))"/> gives an error saying string-join() must have two arguments.

Thanks,
Shailesh

this seems more like it
<xsl:variable name="firstPassToken" select="substring-before(string-join($dest , ''),concat('.',$lastToken))"/>