zizi21
asked on
Java: Output 10%3...
Hi,
I have 2 questions like this:
System.out.println(10.0/3.
My question is how long would 33333333 be and why? coz i printed out and it was pretty long without truncating..
My second question is that :
System.out.println(10%3+5%
I thought it should be 2 instead of 2.0 as both are integers and there is no floats or doubles that allowed it to be promoted.
Pls clarify. thanks
I have 2 questions like this:
System.out.println(10.0/3.
My question is how long would 33333333 be and why? coz i printed out and it was pretty long without truncating..
My second question is that :
System.out.println(10%3+5%
I thought it should be 2 instead of 2.0 as both are integers and there is no floats or doubles that allowed it to be promoted.
Pls clarify. thanks
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ASKER
could she be wrong ?
>>could she be wrong ?
Could be a misprint. Any of those numbers written as a decimal would produce 2.0 for instance
Could be a misprint. Any of those numbers written as a decimal would produce 2.0 for instance
Well, if you execute this testing code you'll see by yourself that System.out.println(10 % 3 + 5 % 2); prints 2, while System.out.println(10.0 % 3.0 + 5.0 % 2.0); prints 2.0. That's because the first numbers are integers, so the result is an integer, while the second option has double, so the result is a double
package test;
public class Test {
public static void main(String[] args) {
System.out.println(10 % 3 + 5 % 2);
System.out.println(10.0 % 3.0 + 5.0 % 2.0);
}
}
package test;
public class Test {
public static void main(String[] args) {
System.out.println(10 % 3 + 5 % 2);
System.out.println(10.0 % 3.0 + 5.0 % 2.0);
}
}
ASKER
thank you..btw, what is the precision for double ?
:-)
ASKER
System.out.println(10 % 3 + 5 % 2); ................. 2.0