asked on

Javascript Dropdown Menu

I'm looking for the Javascript code that loads car makes into a dropdown menu and changes the page to Makes when a selection is made. I have one but I'm not sure it's what I'm looking for. I'll be loading it from a DB.

Thanks,
Michael

mhoggatt1

ASKER

Should be loads Makes and changes to Models.

Peter Hart

I assume you have abandon the other post on javasript menus?
I would use a javascript tools as mentioned www.likno.com they also provide an interface for dynamic menus from databases.
but I think you mean you want the menu to read fom the database? - actually what you want is a standard javasript menu to link to all the pages (likno or the free site I mentioned) and its the pagesget loaded that then access the database to produce the page.

hielo

by menu you mean a selection list?
Do you want an AJAX solution?

mhoggatt1

ASKER

Actually I have a routine Which I would like modified. It's a Javascript routine written for me a couple of years ago. It has a dropdown menu in the left frame that changes the right frame.
I don't know anything about JS. So I need this one modified or you could write a new one for me that does this -
When the selection is made it displays the page (no frames). In this case the variable action_name will be in the menu and it will link to directory_link which is a php page.

Here's my code -

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<Script language="JavaScript"></Script>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<title>bsd_select.php</title>
</head>
<body>
<form>
Search the Database <br>
<select style="width:125px" name="menu1" onChange="jumpMenu('parent.mainFrame',this,0)"><option>Make a Selection</option>
<?php
$include_path = "";
require_once($include_path. 'uis.php');
require_once($include_path. 'myconfig.php');

$i=0;
$j=0;

// $result = mysql_query("SELECT DISTINCT ministryID, ministry_name, ministry_link FROM ".$myconfig->dt['ministries']." ORDER BY ministry_name ASC") or die("Sql error : " . mysql_error());
$result = mysql_query("SELECT DISTINCT jz_directoryID, action_name, directory_link FROM ".$myconfig->dt['jz_directory']." ORDER BY action_name ASC") or die("Sql error : " . mysql_error());

while ($row = mysql_fetch_array($result)) {
echo "<option value=\"{$row['directory_link']}?id={$row['jz_directoryID']}\">".$row["action_name"]."</option>\n";
}

?>
</select>
</form>

<?php
?>
</body>
</html>

hielo

Try changing:
eval(targ+".location='"+selObj.options[selObj.selectedIndex].value+"'");
to
eval(top.location='"+selObj.options[selObj.selectedIndex].value+"'");

hielo

Better yet, change
onChange="jumpMenu('parent.mainFrame',this,0)"
to
onChange="jumpMenu('top',this,0)"

ASKER CERTIFIED SOLUTION

hielo

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mhoggatt1

ASKER

Works great ! Thanks you very much for the rewrite. I increased the points to 500 for the expert service. Hope to do business with you again.

Michael

mhoggatt1

ASKER

I posted the same thing at this address -
https://www.experts-exchange.com/questions/22905510/Java-code-modify.html

Which han't been replied to. Just post your rewrite to this one and I'll give you another 500 poins !

hielo

Thank you very much. You are now in my "preferred customer" list