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Java : Urgent - Unary

zizi21 asked
Last Modified: 2010-03-30
Sorry for the english. Sitting for exam so a bit panic. pls help...

I have a program like below:

public static void main(String [] args){

int x=3;
int y;

y=x++ % ++x;


When i ran y is 3 and x is 5. I read from book, it says that unary operators are evaluated from right to left..
So, if this is the case, ++x is evaluated first ( x=4) , then , x++, so, x=4, y=0 and not 3...pls clarify
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