troubleshooting Question
Java : Urgent - Unary
Hi,
Sorry for the english. Sitting for exam so a bit panic. pls help...
I have a program like below:
public static void main(String [] args){
int x=3;
int y;
y=x++ % ++x;
System.out.println(y);
System.out.println(x);
}
}
When i ran y is 3 and x is 5. I read from book, it says that unary operators are evaluated from right to left..
So, if this is the case, ++x is evaluated first ( x=4) , then , x++, so, x=4, y=0 and not 3...pls clarify
Sorry for the english. Sitting for exam so a bit panic. pls help...
I have a program like below:
public static void main(String [] args){
int x=3;
int y;
y=x++ % ++x;
System.out.println(y);
System.out.println(x);
}
}
When i ran y is 3 and x is 5. I read from book, it says that unary operators are evaluated from right to left..
So, if this is the case, ++x is evaluated first ( x=4) , then , x++, so, x=4, y=0 and not 3...pls clarify
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