Java : Urgent - Unary

Hi,
Sorry for the english. Sitting for exam so a bit panic. pls help...

I have a program like below:

public static void main(String [] args){

int x=3;
int y;

y=x++ % ++x;

System.out.println(y);
System.out.println(x);
}
}

When i ran y is 3 and x is 5. I read from book, it says that unary operators are evaluated from right to left..
So, if this is the case, ++x is evaluated first ( x=4) , then , x++, so, x=4, y=0 and not 3...pls clarify