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Ereg_replace

Posted on 2007-11-13
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Last Modified: 2012-06-21
I have a question in reference to the ereg_replace function in PHP. How exactly do you make it work and how does the syntax work? I find tons of code for this function, but I do not understand how to organize the brackets of items you want to replace. I have this simple ereg_replace function on my site that removes the $ and % and , for a blank space.

$loanamount=ereg_replace("[$%,]","",$_POST['loanamount']);

Thanks. Maybe a little tutorial on this function will do.
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Question by:jcbodyworks
3 Comments
 
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Expert Comment

by:nizsmo
ID: 20275568
so you actually want to replace the $ and % character with a blank space?also the comma?

something like this then:

<?php
      $test = "\$mydkjsi % this";
      $loanamount=ereg_replace("[\$\%,]","",$test);
      echo $loanamount;
?>
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Expert Comment

by:Antonio Estrada
ID: 20275575
ereg_replace gets three arguments, all of them separated by the commas. The first argument is the string to be replaced, the second argument is what will replace the string given on the first argument and the third argument is where it will search for it.

So, ereg_replace("something","SOMETHINGDIFFERENT","this string shows something"); will output "this string shows SOMETHINGDIFFERENT.

The brackets used there state that ANY $, % or , will be replaced by "" (a blank space)

More information here: http://www.php.net/ereg_replace

-V
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Accepted Solution

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steelseth12 earned 2000 total points
ID: 20275606
Firstly i would suggest using
preg_replace()
http://www.php.net/manual/en/function.preg-replace.php

that has perl compatible syntax and its faster than ereg_replace

As for regular expression syntax have a look here

http://docs.python.org/lib/re-syntax.html
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