Fastest way in PERL to compare dates in the following form: YYYY-MM-DD hh:mm:ss

How can you compare dates in PERL with the following date format:YYYY-MM-DD hh:mm:ss
For example: 06-10-26 13:00:06 is greater than 06-10-26 11:27:28
angelskyAsked:
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ozoCommented:
if( '06-10-26 13:00:06' gt '06-10-26 11:27:28' ){ print 'greater' }
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TalmashCommented:
Y2K bug...
you noted YYYY and used YY...

another issue, moving to
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TintinCommented:
Your description and sample data don't match.  Which is correct?
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angelskyAuthor Commented:
Sorry my mistake...
 2006-10-26 13:00:06 is greater than 2006-10-26 11:27:28
Because "2006-10-26 13:00:06 " is later than "2006-10-26 11:27:28"
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angelskyAuthor Commented:
$dateA = "2006-10-26 13:00:06";
$dateB = "2006-10-26 11:27:28";

How can I say that dateA is after dateB?
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TintinCommented:
As ozo has already shown

$dateA = "2006-10-26 13:00:06";
$dateB = "2006-10-26 13:27:28";

if ($dateA gt $dateB) {
  print "$dateA is later than $dateB\n";
}
else {
  print "$dateB is later than $dateA\n";
}
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