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Getting recursive values of sub records in MSSQL 2005

Posted on 2007-11-14
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Last Modified: 2011-09-20
I have a table called "categories" which contains all categories of "widgets".  Categories can be "sub_of" as well.  There is a field.  The structure looks like.

category_id int id
category_name varchar (50)
sub_of int

The data look like this

category_id             category_name                        sub_of
--------------------------------------------------------------------------
1                             Widgets                                        0   -  this is the root.
2                             Nice Widgets                                 1
3                             Cool Widgets                                1
4                             Very Cool widgets                         3

In my "widgets" table there is reference (fk) to category_id to categorize the widgets.

Question - I need to create a query to quickly return the contents and counts in each category.

For example, if I had 10 widgets total, the counts would look like:

>Widgets (10)
    >Nice Widgets (5)
    >Cool Widgets (5)   (note: 3 in this category and two below).
        > Very Cool Widgets (2)

So if I ask for all Widgets in "widgets" I get all widgets not only spefically in that category, but in all sub categories as well.  I also need the counts in similar manner.

I need actual code examples please.

Thank you.
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Question by:ccleebelt
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4 Comments
 
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Expert Comment

by:Guy Hengel [angelIII / a3]
ID: 20282542
the hierarchical part is easy, using the CTE method in SQL 2005...
did you achieve that already?
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Author Comment

by:ccleebelt
ID: 20282684
no - I am just getting this started.
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Accepted Solution

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Guy Hengel [angelIII / a3] earned 500 total points
ID: 20283312
ok, lets' see to get part 1 done, the recursion without the counts yet
http://msdn2.microsoft.com/en-us/library/ms186243.aspx
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Author Comment

by:ccleebelt
ID: 20283498
actually, this does it...thanks.  I can just add the count(*) to the last query and go from there.
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