asked on

Array in an Array

When I am retrieving the value for the $_FILES super global I am getting Array returned. How do I get the value of the elements inside the array to get returned?

<label for="file">File: <?php echo $details['file'] ?></label> 

Form
<?php foreach ($cars as $car => $details) { ?>
<h3><?php print $car ?></h3>
<label for="format">Format: <?php echo $details['format'] ?></label> 
<label for="rotation">Rotation(%): <?php echo $details['rotation'] ?></label> 
<label for="size">Size:
<?php echo $details['724x90']; ?>  
<?php echo $details['300x250']; ?>  
<?php echo $details['160x600']; ?></label>      
<label for='other'>Other: <?php echo $details['othertx'] ?> </label> 
<label for="layout">Layout: <?php echo $details['layout'] ?></label> 
<label for="bannerlink">Banner Link: <?php echo $details['bannerlink'] ?></label> 
<label for="file">File: <?php echo $details['file'] ?></label> 
<label for="dspecific">Deal Specifics: <?php echo $details['dspecific'] ?></label> 
<label for="disclaimer">Disclaimer: <?php echo $details['disclaimer'] ?></label> 
<?php } ?>

SOLUTION

steelseth12

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SOLUTION

jgordos

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SOLUTION

jgordos

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taynet29

ASKER

All the arrays are being printed on the "Work Order Review" page. All I am asking is how do I get the variable to print as an array. Keep in mind it is being stored as an Array in $details. Then the $_FILES array. As a result, <?php echo $details['file'] ?> prints ---> Array.

What I have tried is
<?php if(isset($_FILES["file"][0])) ?>
<?php if(isset($_FILES["file"]["name"])) ?>
<?php if(isset($details["file"][1])) ?>
<?php if(isset($details["file"]["name"])) ?>

They all do not return a value.

Please let me know what I am doing incorrectly. How do I print the file name?

ASKER CERTIFIED SOLUTION

steelseth12

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